[SOLVED] Don't know how to display a image in php.

[Redlightpacket]

Here is my code right here. I need some help with displaying the image in the code. I might be having a bug.

$query = "SELECT * FROM picture_tb";

$result = mysql_query($query)
or die("Query failed: " . mysql_error());


while ($row = mysql_fetch_assoc($result))
{
echo'<table border="1">
<tr>
<td>';echo $row["id"];echo'</td>




<td><IMG SRC="';echo'file:///C:/wamp/www/';$row['picture'];echo'">';echo'</td>




<td>';echo $row["title"]; echo'</td>
<td>';echo $row["desc"]; echo'</td>


</tr>
</table>
';
}
////////////////////////////////////////////////////////code]

[gijew]

Try replacing

<td><IMG SRC="';echo'file:///C:/wamp/www/';$row['picture'];echo'">';echo'</td>

 

with

 

<td><IMG SRC="'C:/wamp/www/' . $row['picture'] . '"></td>

[Stephen68]

Hello

 

I'm not sure about weather you should have those semi's and echo's that way.... I could be wrong though.

 

<td>';echo $row["id"];echo'</td>

 

I have not seen code laid out this way but that doesn't mean it is wrong either

try

 

$query = "SELECT * FROM picture_tb";

$result = mysql_query($query) or die("Query failed: " . mysql_error());


while ($row = mysql_fetch_assoc($result))
{
echo'<table border="1"><tr><td>';
echo $row["id"];
echo'</td><td><IMG SRC="';
echo "file:///C:/wamp/www/".$row['picture']."\"></td><td>";
echo $row["title"]; echo'</td><td>';
echo $row["desc"];
echo'</td></tr></table>';
}
////////////////////////////////////////////////////////code]

 

hope this helps in some way

[Redlightpacket]

I'll try what yall are talking about

[Redlightpacket]

I changed this around a little bit and it worked

 

I changed file:// to http://

 

 

echo "http://localhost/".$row['picture']."\"></td><td>";

 

but thanks for the help everybody