vikela Posted March 20, 2009 Share Posted March 20, 2009 PHP Online opinion poll script using MySQL I am trying to run an opinion poll on my homepage and i have managed to get a script and include it into my homepage..problem is that the results are appearing on a different window?how can i make the results appear on the same spot where the poll is displayed?here is the code i have so far. display poll Code: [select] <? //$dbservertype='mysql'; $servername='myserver'; // username and password to log onto db server $dbusername='myusername'; $dbpassword='mypasswd'; // name of database $dbname='mydb'; connecttodb($servername,$dbname,$dbusername,$dbpassword); function connecttodb($servername,$dbname,$dbuser,$dbpassword) { global $link; $link=mysql_connect ("$servername","$dbuser","$dbpassword"); if(!$link){die("Could not connect to MySQL");} mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error()); } /* Read the session id to display the poll result link */ if(mysql_fetch_object(mysql_query("select s_id from plus_poll_ans where s_id='$s_id'"))){ //echo "<a href=polling/view_poll_result.php>View the poll result</a>";} echo"<a href=polling/view_poll_result.php onclick=MM_openBrWindow('polling/view_poll_result.php','poll','width=350,height=200')>View Result</a>";} /* You can keep the parts below inside the else area if you don't want to show the form for the visitors who have already participated in the poll */ $qst_id=2; // Change this ID for a different poll $query=mysql_fetch_object(mysql_query("select * from plus_poll where qst_id=$qst_id")); echo " <form method=post action=poll_displayck1.php> <input type=hidden name=qst_id value=$qst_id> <table border='1' cellspacing='0' width='120' id='AutoNumber1'> <tr> <td width='100%'> <font face='Verdana' size='2' >$query->qst</font></td> </tr> <tr> <td width='100%' > <table border='0' cellspacing='0' width='100%' cellpadding='0'> <tr bgcolor='#f1f1f1'> <td width='10%'><input type='radio' value='$query->opt1' name='opt'></td> <td width='90%'><font face='Verdana' size='2' >$query->opt1</font></td> </tr> <tr> <td width='10%'><input type='radio' value='$query->opt2' name='opt'></td> <td width='90%'><font face='Verdana' size='2' >$query->opt2</font></td> </tr> <tr bgcolor='#f1f1f1'> <td width='10%'><input type='radio' value='$query->opt3' name='opt'></td> <td width='90%'><font face='Verdana' size='2' >$query->opt3</font></td> </tr> <tr> <td width='10%'><input type='radio' value='$query->opt4' name='opt'></td> <td width='90%'><font face='Verdana' size='2' >$query->opt4</font></td> </tr> </table> </td> </tr> <tr> <td width='100%' bgcolor='#ffff00' align=center> <font face='Verdana' size='2' ><input type=submit value=Submit></form></td> </tr> </table> "; /* End of the form displaying the poll question and its four options for selection */ ?> </script> <center> <a href="polling/view_poll_result.php">View Results</a><br> <br> /show results connecttodb($servername,$dbname,$dbusername,$dbpassword); function connecttodb($servername,$dbname,$dbuser,$dbpassword) { global $link; $link=mysql_connect ("$servername","$dbuser","$dbpassword"); if(!$link){die("Could not connect to MySQL");} mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error()); } ////////////////////////////// echo "<font size='2' face='Verdana' color='#000000'> ( Poll ID = 1)</font>"; $qst_id=2; // change this to change the poll /* Find out the question first */ $fg=mysql_query("select qst from plus_poll where qst_id='$qst_id'"); $row=mysql_fetch_object($fg); echo "<br><b><br>$row->qst</b><br>"; // display the question /* for percentage calculation we will find out the total number of answers ( options submitted ) given by the visitors */ $rt=mysql_num_rows(mysql_query("select ans_id from plus_poll_ans where qst_id=$qst_id")); /* Find out the answers and display the graph */ $query="select count(*) as no,qst,plus_poll_ans.opt from plus_poll,plus_poll_ans where plus_poll.qst_id=plus_poll_ans.qst_id and plus_poll.qst_id='$qst_id' group by opt "; $rs=mysql_query($query); echo "<table cellpadding='0' cellspacing='0' border='0' >"; while($noticia = mysql_fetch_array($rs)){ echo "<tr> <td width='40%' bgcolor='#F1F1F1'> <font size='1' face='Verdana' color='#000000'>$noticia[opt]</font></td>"; $width2=$noticia['no'] *50 ; $ct=($noticia[no]/$rt)*100; $ct=sprintf ("%01.2f", $ct); // number formating echo "<td width='10%' bgcolor='#F1F1F1'> <font size='1' face='Verdana' color='#000000'>($ct %)</font></td><td width='50%' bgcolor='#F1F1F1'><img src='graph.jpg' height=10 width=$width2></td> </tr>"; echo "<tr> <td bgcolor='#ffffff' colspan=2></td></tr>"; } echo "</table>"; echo "</font>"; ?> can somebody please help! Quote Link to comment Share on other sites More sharing options...
jlavik Posted March 20, 2009 Share Posted March 20, 2009 <a href="polling/view_poll_result.php">View Results</a><br> When they click to view the results, they are being directed to a different page, view_poll_result.php. You might want to check out the poll at http://www.w3schools.com/php/php_ajax_poll.asp. It's much less complicated than the one you're using, but it *does* display results in the same spot as you desire. Perhaps it will point you in the right direction. Quote Link to comment Share on other sites More sharing options...
phpMyTony Posted March 23, 2009 Share Posted March 23, 2009 Use the [code] [/code] tags - it will look easier Quote Link to comment Share on other sites More sharing options...
vikela Posted March 25, 2009 Author Share Posted March 25, 2009 <a href="polling/view_poll_result.php">View Results</a><br> When they click to view the results, they are being directed to a different page, view_poll_result.php. You might want to check out the poll at http://www.w3schools.com/php/php_ajax_poll.asp. It's much less complicated than the one you're using, but it *does* display results in the same spot as you desire. Perhaps it will point you in the right direction. thanks but i want 1 that uses a db Quote Link to comment Share on other sites More sharing options...
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