[SOLVED] How do I format a script response to a website post?

[mrfitz]

??? ???

Need a little help...

I use CURL to send headers to a script on another website (other domain where the script is running on).

At the end of the script I do a return and the results from the script are displayed on the Calling webpage.

The problem is the I am returning  a comma delimited string and it just displays the string on the webpage.  I would really like to be able to grab the string without displaying it, then parse it into fields and display it in a table, but the script does not come back into a field.  It just displays on the page, I can't seem to capture it into a "receiving" string that I can parse out.

The question is ...

How do I get the response back into a string that I can parse?

 

Here is a snip of the "end" of the script on the domain I am getting the response string from:

 

//////

default:

    $error_code = 3;

$output = "0,0,0," . error_report($error_code).";";

    fwrite($log, "OUT Vals: " . $output . "\r\n\r\n");

   

}

fclose ($log);

return;

?>

///////

  as you can see it is just a simple "return;".

 

A snip of the calling web page's script is here:

/////////////////

function get_bal2(){

?>

<div align="center" class="content">

<h1>Balance Request</h1>

<h2>Current Balance</h2>

</div>

<?php

send_request();

return;

}

 

 

function send_request(){

$req = $_POST;

array_pop($req);

$URL="xxxxxxxxx.com/yyyyyyy/rrrrr.php";

$ch = curl_init(); 

curl_setopt($ch, CURLOPT_URL,"http://$URL");

curl_setopt($ch, CURLOPT_POST, 1);

curl_setopt($ch, CURLOPT_POSTFIELDS, $req);

curl_exec ($ch);   

curl_close ($ch);

return;

}

///////////////////////

and here is a screen scrape of the result webpage:

////////////////////

Balance Request

Current Balance

25.00,2009-03-22,1;

////////////////////

 

As you can see the response sting is there but is displayed as it is sent from the script on the domain I am getting the response string from.

 

Please help.

 

Thanks in advance,

Mrfitz

 

 

 

[mrfitz]

Fixed my own problem with:

function send_request(){

$req = $_POST;

array_pop($req);

$URL="zzzzzzzzzzz.com/yyyyyyyyy/xxxxxxxx.php";

$ch = curl_init(); 

curl_setopt($ch, CURLOPT_URL,"http://$URL");

curl_setopt($ch, CURLOPT_POST, 1);

curl_setopt($ch, CURLOPT_POSTFIELDS, $req);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

        // $output contains the output string

$output = curl_exec($ch);   

curl_close ($ch);

return($output);

 

}

 

just call this and it works!!