preg_match_all problem with pattern

[JohnyBazooka]

Hello there,

 

as you can see i am totaly newbie here, so at first - sorry for my bad english..

And sorry that my first post is asking for help, but i am really at deadend. I am was googling more than 4hours my problem, but i experienced that i wont find solution for my problem and i have to study regex

 

I have bookmarks some webpages with regex (http://www.regular-expressions.info/ for example), but i need make one pattern for my web. Please, if someone can help with this >

 

i have this source code:

<td style="padding: 10px; text-align: center; font-weight: bold; font-size: 36px; color: white; background-color: rgb(117, 132, 171);">

            61%            </td>

 

and i want from there that number with % (it can be other number ofcourse)... Please can you help me with that pattern?

 

 

[Jagarm]

Try the following:

<[^>]*>([^\r]*?)</.*>

the result that you get from there may contain additional spaces which you must trim it.

[JohnyBazooka]

Thanks for quick reply, but didnt help that code...

Results > more than i want... Is possible to have that style=.... in that pattern? It is only way to match only that one result that i want.

[nrg_alpha]

You want the numbers then the %?

 

Example:

$str = <<<DATA
<td style="padding: 10px; text-align: center; font-weight: bold; font-size: 36px; color: white; background-color: rgb(117, 132, 171);">
             61%            </td>
DATA;

preg_match('#<td.*?style=[^>]+>.*?(\d+%).*?</td>#s', $str, $match);
echo $match[1]; // outputs 61%

 

Note, after the td, I put .*? in case there might be some stuff between that, like <td class="whatever" style=.....> In either case, it should work.

[JohnyBazooka]

That work too, but i have more results that i want too... Can you please make pattern with exact formula in it >

 

<td style="padding: 10px; text-align: center; font-weight: bold; font-size: 36px; color: white; background-color: rgb(117, 132, 171);">  61%           </td>

 

I am really happy, that you want to help me

[nrg_alpha]

I don't think you understand (unless I am missing something here).

 

The (\d+%) part in the pattern captures a digit one or more times, followed by the % sign, and stores that into the variable $match[1]. Are you using $match[1]? Can you provide a small sample of code where you are using this, as well as what you are checking? Because when you run my small sample, it will only give 61%.

[JohnyBazooka]

Look at result of that array >

Array ( [0] => 100% [1] => 100% [2] => 100% [3] => 75% [4] => 61% [5] => 100% [6] => 100% ) Array

So there is more numbers with %....

Look at this page > here is example from what i need to download that text...

http://www.csfd.cz/film/221839-hluboko-v-gangu-waist-deep/

 

You will need this >

 

function curl_file_get_contents($url) {

$c = curl_init();

curl_setopt($c, CURLOPT_RETURNTRANSFER, 1);

curl_setopt($c, CURLOPT_URL, $url);

$contents = curl_exec($c);

curl_close($c);

return $contents;

}

$data = curl_file_get_contents("http://www.csfd.cz/film/221839-hluboko-v-gangu-waist-deep/");

 

 

Is possible to match exactly that one number 61%?

[nrg_alpha]

Well, you could change the preg line to read:

 

if(preg_match('#<td.*?style=[^>]+>.*?(61%).*?</td>#s', $data)){
   // do something
}

 

Is that what you want?

[JohnyBazooka]

Sorry, but no  :-\

 

That number is not every time 61, but can vary... This one number is between that td with that style...

 

http://www.csfd.cz/film/1644-kmotr-godfather-the/

http://www.csfd.cz/film/10135-forrest-gump/

 

look at that > numbers with % - that is rating... i want to use that ratings on my web... i can that manually type, but i think this is time for preg_match_all

[nrg_alpha]

Then my suggestion is to use my first preg example, and search through your array using foreach and track down which percent you want.

[JohnyBazooka]

100% [1] => 100% [2] => 100% [3] => 75% [4] => 61% [5] => 100% [6] => 100%

- i dont know which is the right one, when i see this...

There is right number that 61, but only because i know that it is 61...

 

[nrg_alpha]

For example:

 

$arr = array('100%', '100%', '100%', '75%', '61%', '100%', '100%'); // an example array
foreach ($arr as $val) {
if($val == '61%'){
	// do something
}
}

 

So instead of $arr, use the array name you are using instead. I would suggest doing some php tutorials on arrays, and different loops, like for, foreach, etc.. (just google it, there is plenty of material floating around to help you out).

[sasa]

preg_match('/<td style=[^>]+>\s*(\d+%)\s*</', $str, $match);
echo $match[1];

[JohnyBazooka]

preg_match('/<td style=[^>]+>\s*(\d+%)\s*</', $str, $match);
echo $match[1];

Thank you very much sasa. This is exactly what i need. I test it for few pages and it seems to work perfectly

 

Btw. thanks everyone who try to help!