displaying image using url stored in database

[kevdoug]

Hi I fairly new to PHP and what I am trying to achieve is to retrieve an image stored on the server using the url I have stored in the database. I can retrieve the url from the database and display it in text form but I am struggling to diplay the image. I have the code I am using below.

$img = OCIResult($stmt,'IMAGE');
     
      echo $img; this will display the text e.g. C:\winter.jpg
     
echo "<img src= "$img"\" >"; This is how I am trying to display the image
     

[ChaosXero]

Try this:
[code]echo "<img src=' " . $img . "' >";[/code]
You needed ' ' around the image source and .'s to get out of the "" and use the variable. instead of $img.

[kevdoug]

your a *star* worked first time you would know how many hours ive spent on this.

Cheers

[ChaosXero]

No problem.  You might want to read up some more on single and double quotes.  I know they drive me insane as I can NEVER keep them straight.  It's hard to remember which does what with variables and escapes and all that.

[kevdoug]

Hi ChaosXero

You couldn't tell me how to reduce the size of the image aswell as it has come out huge!

[ChaosXero]

Just edit the echo so that it contains an image size:
[code]echo "<img src=' " . $img . "' height='200' width='200'>";[/code] 

you could change those to variables too if you wanted to.

[kevdoug]

Cheers I seem to be getting some where now.