[SOLVED] Simple Date question

[phpretard]

I need to display the current year + 5 more.

 

Here is what I have...

 

$EXPYear=date(Y);

for ($i=$i; $i <= 5; $i++){

echo <option>This Year And Five More</option>;

}

 

Obviously doesn't work...

 

Thank you!

[phpretard]

Not Simple?

[zizzi0n]

How about:

 

$fiveyears  = mktime(0, 0, 0, date("m"),   date("d"),   date("Y")+5);

 

Haven't tried it but its basically straight from the php.net site

[killah]

echo date('Y').' and 5 year\'s ahead = '.date('Y')+5;

[phpretard]

Thank you

 

$EXPYear=date(Y);
$Years5=date('Y', mktime(0, 0, 0, 60, 32, $EXPYear));

for ($i=$EXPYear; $i <= $Years5; $i++){

echo "<option>$i</option>";

}

[Salkcin]

or you could simply do like this,

for ($i=date('Y'); $i < (date('Y') + 5); $i++)
{
echo "<option>$i</option>";
}

[killah]

Pre-increment is alway's better i think.

 

for($i = date('Y'); $i <= (date('Y') + 5); ++$i)  {
    echo '<option value="'.$i.'">'.$i.'</option>;
}

[PFMaBiSmAd]

Calling functions in the for() statement to get fixed starting and ending values, results in the slowest execution time.