boralyl Posted July 21, 2006 Share Posted July 21, 2006 I tried to simplify it, but let me just post all of the major components of the code.First the code used to envoke all of these classes:[code]<?php $q = new Albums(); $q->Album_id->equals(3); $q->debugLevel(2); $q->find(); while($q->fetch()) { echo $q->Album_id.'<br />'; }?>[/code]The important part of the Albums class:[code]<?phprequire_once("DataObject.php");require_once("DataObjectColumn.php");class Albums extends DataObject{ var $Id = null; var $Album_Name = null; function Albums() { $this->DataObject(); $this->clearObject(); } function clearObject() { $this->Id = new DataObjectColumn($this, 'Id', false); $this->Album_Name = new DataObjectColumn($this, 'Album_Name', true); }?>[/code]The DataObjectColumn class:[code]<?php class DataObjectColumn { var $column = null; var $requires_quote = null; var $data_object = null; function DataObjectColumn(&$dataobject, $column_name, $requires_quote) { $this->data_object =& $dataobject; $this->column = $column_name; $this->requires_quote = $requires_quote; } function equals($value) { $sql = $this->data_object->quoteID($this->column) .' = '. $this->data_object->quote($value); $this->data_object->addWhere($sql); } }?>[/code]And finally the declaration of vars, constructor and member functions used above I included in the DataObject class[code]<?phprequire_once("DataLayer.php"); class DataObject extends DataLayer { var $result = null; var $args = null; var $sorts = null; var $whereConditions = null; var $selectDistinct = false; var $debugLevel = 0; var $test = 0; function DataObject() { $this->DataLayer(); $this->args = array(); $this->sorts = array(); unset($this->result); } function quote($data) { if(!is_object($data)) return '\'' . mysql_real_escape_string($data) . '\''; else return '\'' . mysql_real_escape_string($data->data_object) . '\''; } function quoteID( $field ) { return "`$field`"; } function addWhere($sql) { if($this->whereConditions != null) { $this->whereConditions .= ' AND '.$sql; } else { $this->whereConditions = $sql; } } function find() { echo $this->whereConditions;?>[/code]Now when I echo that variable it is null. Even though if you echo it in addWheres it has the value of 3. The DataLayer class just opens up a link to the database. Any ideas as to what I am doing wrong? Quote Link to comment https://forums.phpfreaks.com/topic/15208-class-variables-not-holding-values/ Share on other sites More sharing options...
hvle Posted July 21, 2006 Share Posted July 21, 2006 Your code is good! no error in syntax nor structure.You might want to look at other code which accessed $whereContitions and the parent class DataLayer. Quote Link to comment https://forums.phpfreaks.com/topic/15208-class-variables-not-holding-values/#findComment-61463 Share on other sites More sharing options...
boralyl Posted July 21, 2006 Author Share Posted July 21, 2006 This may help...If instead of calling $albums->Album_id->equals(5); I call addWhere directly such as $albums->addWhere('Albumi_id = 5'); The $this->whereConditions holds it's value. It's calling addWhere from equals in the DataObjectColumn class that it isn't working. Yet when I check to see what kind of object it is for both addWhere and equals it is the same type of object..Albums. Quote Link to comment https://forums.phpfreaks.com/topic/15208-class-variables-not-holding-values/#findComment-61746 Share on other sites More sharing options...
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