'if'fing checkbox values.

[Thauwa]

Status - I have an HTML form, which has checkboxes named c1, c2, c3 & c4.

            When checked, the value (thing I want to insert to mysql) must be 'yes', and the remaining must be valued 'no'.  ???

 

Situation- I can't find how to do it.  :-\

 

Help! Does anyone know how to achieve this? Thanks in advance!

[Showcase]

When a checkbox is unchecked, nothing is sent via POST. When a checkbox is checked, it's html value feild is sent. For setting a variable to yes or no if the checkbox is checked or unchecked, you can check it using the isset function.

 

$c1 = (isset($_POST['c1'] ? "yes" : "no");
$c2 = (isset($_POST['c2'] ? "yes" : "no");
$c3 = (isset($_POST['c3'] ? "yes" : "no");
$c4 = (isset($_POST['c4'] ? "yes" : "no");

[Thauwa]

thanks, i'll try it. then, there must be no value to the box in the html?

[Showcase]

Well, in your situation, the value of the checkbox is not being used. So it won't effect the results at all.

[Thauwa]

Thank you! I hope that it works!

[Thauwa]

Cannot I use 'y' instead of 'yes' and 'n' instead of 'no'.

An error occurs when it is, saying that a ') or a ',' must be there

[Yesideez]

$c1=($_POST['c1'] ? "y" : "n");
$c2=($_POST['c2'] ? "y" : "n");
$c3=($_POST['c3'] ? "y" : "n");
$c4=($_POST['c4'] ? "y" : "n");

 

Try that.

[Yesideez]

What the above is equal to:

if ($_POST['c1']) {
  $c1="y";
} else {
  $c1="n";
}

 

You can see that having $_POST['c1'] in the if() on its own just checks if the checkbox was set - isn't checking against a specific value.

[Thauwa]

I think that the new code is correct, because, when the previous code is put,

Parse error: syntax error, unexpected '?', expecting ',' or ')' in D:\Hosting\3577251\html\quiz\submit.php on line 6

 

occurs.

Thanks, I'll try the new one!

[unrelenting]

Might try:

 

$c1=($_POST['c1']) ? "y" : "n";
$c2=($_POST['c2']) ? "y" : "n";
$c3=($_POST['c3']) ? "y" : "n";
$c4=($_POST['c4']) ? "y" : "n";