sungpeng Posted April 2, 2009 Share Posted April 2, 2009 <?php include 'config2.php'; if($_POST[action]=="Update") { $check_result=0; $check_login=mysql_query("select * from users where email='$_POST[user]' and passwd='$_POST[pass]' and pid='$_GET[pid]'"); $check_result=mysql_num_rows($check_login); } if($check_result>0) { $indexnumber=$_GET[pid]; $folder_path="photo/$indexnumber/"; if (file_exists("photo/$indexnumber")) { } else { mkdir($folder_path,0777); } echo $indexnumber; $file_upload_err=0; $max_file_size="10000000"; $max_file_size_kb="500"; $file_upload_err_msg=""; if($_FILES['imagefile']['size']>$max_file_size) { echo "image file too big"; }elseif ($imagefile && ($_FILES['imagefile']['type']!="image/jpeg" && $_FILES['imagefile']['type']!="image/pjpeg")) { $type=$_FILES['imagefile']['type']; echo "image file type wrong"; } }else{ ?> <html> <title>Upload an image to a database</title> <body> <h2>Update with new information</h2> <form name="form" enctype="multipart/form-data" method="post" action="<?php echo"$PHP_SELF?pid=$_GET[pid]"; ?>"> Please insert the images <input type='file' name='imagefile'><br> <br> USER : <input name="user"><br> PASSWORD : <input name="pass"><br> <input type="submit" name="action" value="Update"> </form> </body> </html> <?php } ?> Hi I keep editing the above code but it seem not working. Can anyone help? Parse error: syntax error? Quote Link to comment Share on other sites More sharing options...
sungpeng Posted April 2, 2009 Author Share Posted April 2, 2009 Sorry, the Parse error: syntax error solved, I need it only to upload JPG, but it seem the code still can upload all type of files.. it didn't echo "image file type wrong". Quote Link to comment Share on other sites More sharing options...
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