[SOLVED] How do i make it ignore a prefix ?

jamesxg1 · April 2, 2009

This is complicated so i will explain in as much detail as i can,

Ok what i need to do is make a php page display and image with the following link,

PhotoView?image=UNIQE IMAGE ID HERE!

and and lets say for instance the ID was 123456,

That means that in the images/ folder there is a image called 123456 but i want to be able to put that url in a img src and not have to worry about prefix's i either need the PhotoView to auto get the prefix or to ignore it and not need it to display the picture.

Is this possible ?

Many many thanks,

James.

Yesideez · April 2, 2009

It's possible - you'd need to use fopen() to try and open each file in a loop recording which one it found (.gif, .jpg, .jpeg, .png etc.) then append the extension to the filename then place that inside IMG.

http://uk.php.net/fopen

jamesxg1 · April 2, 2009

It's possible - you'd need to use fopen() to try and open each file in a loop recording which one it found (.gif, .jpg, .jpeg, .png etc.) then append the extension to the filename then place that inside IMG.

http://uk.php.net/fopen

Ok a little confussed,

but heres the only thing i could come up with

<?php

$usid = mysql_real_escape_string(trim(intval($_GET['memberid'])));

$search = @fopen("images/", "r");

if ($search) {
    while (!feof($search)) {
        $buffer = fgets($search, $usid);
        echo $buffer;
    }
    fclose($search);
}

?>

Yesideez · April 2, 2009

Something similar...

$arrFileTypes=array('gif','jpg','jpeg','png');
foreach ($arrFileTypes as $type) {
  if ($fh=fopen($picname.$type,"r")) {
    $found=$type;
    close($fh);
  }
}

jamesxg1 · April 2, 2009

Something similar...

$arrFileTypes=array('gif','jpg','jpeg','png');
foreach ($arrFileTypes as $type) {
  if ($fh=fopen($picname.$type,"r")) {
    $found=$type;
    close($fh);
  }
}

Ok, but where would i put the folder for it to search ?

jamesxg1 · April 2, 2009

<?php

$picname = mysql_real_escape_string(trim(intval($_GET['memberid'])));

$arrFileTypes=array('gif','jpg','jpeg','png');
foreach ($arrFileTypes as $type) {
  if ($fh=fopen($picname.$type,"r")) {
    $found=$type;
    close($fh);
  }
}

?>

am i correct with this ?

jamesxg1 · April 2, 2009

ok i got it working except one thing :S

Warning: fopen(1gif) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1jpg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1jpeg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1png) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

it seems there is no "." between the name and prefix :S how do i do this ?

jamesxg1 · April 2, 2009

ok i got it working except one thing :S

Warning: fopen(1gif) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1jpg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1jpeg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

Warning: fopen(1png) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\PhotoView.php on line 7

it seems there is no "." between the name and prefix :S how do i do this ?

Please someone help.

Yesideez · April 2, 2009

  if ($fh=fopen($picname.'.'.$type,"r")) {

Yesideez · April 2, 2009

As for where to put the folder...

  if ($fh=fopen('images/'.$picname.'.'.$type,"r")) {

jamesxg1 · April 2, 2009

As for where to put the folder...
  if ($fh=fopen('images/'.$picname.'.'.$type,"r")) {

ok iv done the following and here's the result

Warning: fopen(images/1.gif) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\ProfilePhoto.php on line 21

Warning: fopen(images/1.jpg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\ProfilePhoto.php on line 21

Warning: fopen(images/1.jpeg) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\social\ProfilePhoto.php on line 21

Fatal error: Call to undefined function close() in C:\xampp\htdocs\social\ProfilePhoto.php on line 23

the image i am trying to get is in the directory and is a PNGG i can see the error for finding the PNG file is gone but it still isnt displaying anything :S

Yesideez · April 2, 2009

I don't know where your images are stored - all that is saying is that fopen() cannot find them.

images/ is obviously the wrong folder - you'll have to change images/ to where your images are kept.

gaza165 · April 2, 2009

It cannot find the images... check your directory structure and check that it is looking in the correct place for the images.

jamesxg1 · April 2, 2009

I don't know where your images are stored - all that is saying is that fopen() cannot find them.

images/ is obviously the wrong folder - you'll have to change images/ to where your images are kept.

i have a folder named images with the follwing (Got this from CMD)

Directory of C:\xampp\htdocs\social

02/04/2009 11:24 <DIR> .

02/04/2009 11:24 <DIR> ..

30/03/2009 15:22 <DIR> admin

02/04/2009 09:49 <DIR> css

23/05/2007 02:40 <DIR> db

30/03/2009 15:22 5,074 EditInfo.php

30/03/2009 15:22 5,243 EditPassword.php

01/04/2009 10:56 1,627 Functions.php

02/04/2009 11:26 <DIR> images

02/04/2009 11:30 5,818 Index.php

01/04/2009 18:28 <DIR> js

01/04/2009 21:27 4,781 Login.php

28/03/2009 20:03 728 Logout.php

30/03/2009 15:22 5,108 LostPassword.php

02/04/2009 09:14 1,739 PostComment.php

02/04/2009 10:25 5,248 Profile.php

02/04/2009 11:30 478 ProfilePhoto.php

30/03/2009 15:22 1,484 Register.php

01/04/2009 11:13 4,756 SaveUser.php

02/04/2009 09:59 3,411 ViewAllComments.php

13 File(s) 45,495 bytes

7 Dir(s) 37,172,310,016 bytes free

C:\xampp\htdocs\social>cd /images

C:\xampp\htdocs\social\images>dir

Volume in drive C has no label.

Volume Serial Number is D0D5-566F

Directory of C:\xampp\htdocs\social\images

02/04/2009 11:26 <DIR> .

02/04/2009 11:26 <DIR> ..

15/02/2007 00:34 1,319 1.PNG

02/04/2009 09:17 4,863 apply.gif

05/06/2008 11:13 3,403 bak_09.png

15/02/2007 00:34 3,735 continue.png

15/02/2007 00:34 1,613 exclam.PNG

15/02/2007 00:34 204 index.php

15/02/2007 00:34 1,319 not.PNG

15/02/2007 00:34 55,598 pop.png

15/02/2007 00:34 1,525 suc.PNG

15/02/2007 00:34 19,405 works.png

10 File(s) 92,984 bytes

2 Dir(s) 37,172,310,016 bytes free

C:\xampp\htdocs\social\images>

Thats my folder structure and the image is in there as the image i am looking for is a .PNG file and when i go to view it that are every other prefix error except .PNG but when i view something else that prefix error goes aswell :S

jamesxg1 · April 2, 2009

i also put this * ProfilePhoto.php?memberid=bak_09 * in a image src and it didnt work :S

Yesideez · April 2, 2009

LOL

my bad!!!

Noticed it was a warning and not an error!!!

if ($fh=@fopen('images/'.$picname.'.'.$type,"r")) {

The "@" suppresses the error - use with caution when using this as you can hide valid error messages if used incorrectly. In this instance it's OK because we know this WILL definitely fail at some point.

Just remember the "@" is there so if you experience problems in the future you can remove it for testing.

Now just make sure you have files in the images/ folder for it to detect!

jamesxg1 · April 2, 2009

LOL

my bad!!!

Noticed it was a warning and not an error!!!
if ($fh=@fopen('images/'.$picname.'.'.$type,"r")) {
The "@" suppresses the error - use with caution when using this as you can hide valid error messages if used incorrectly. In this instance it's OK because we know this WILL definitely fail at some point.

Just remember the "@" is there so if you experience problems in the future you can remove it for testing.

Now just make sure you have files in the images/ folder for it to detect!

lol,

sorted all except for this. . . .

Fatal error: Call to undefined function close() in C:\xampp\htdocs\social\ProfilePhoto.php on line 23

jamesxg1 · April 2, 2009

sorted its suppost to be fclose() not close() lol

jamesxg1 · April 2, 2009

but not the script is error free i need to address the issue of. . . i cant display the images

jamesxg1 · April 2, 2009

does anyone know how i can do this ?

Yesideez · April 2, 2009

Does it actually come up with a success on finding any of the images?

If it does - you know the folder the images are stored in, the name of the file and its extension.

Just ECHO out the HTML to link to the image or if you want to be really eager use GD library functions to make the image and display it to the browser.

jamesxg1 · April 2, 2009

Does it actually come up with a success on finding any of the images?

If it does - you know the folder the images are stored in, the name of the file and its extension.

Just ECHO out the HTML to link to the image or if you want to be really eager use GD library functions to make the image and display it to the browser.

no, the image on the url is PhotoProcess.php?memberid=bak_09 but it is not displaying it at all it just has the browsers default "not found" image :S

jamesxg1 · April 2, 2009

<img src="PhotoProcess.php?memberid=bak_09" alt="picture" width="253" height="163">

is the code i have

jamesxg1 · April 2, 2009

is it something i am doing wrong ?

Yesideez · April 2, 2009

Just after $found=type add this line:

echo 'FOUND:'.$type;

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[SOLVED] How do i make it ignore a prefix ?

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