justAnoob Posted April 4, 2009 Share Posted April 4, 2009 The following works great and display properly except for the part in the table where I want a letter to appear. The letter is just saved in my images folder on my server. The letter will eventually get a link, but I'm not worried about that right now. look below at the commented sections for what my problem is. <?php echo "<tr><td>"; echo '<img src="' . $row['imgpath'] . '" width="125" alt="" />'; //works good echo "</td><td>"; echo $row['student']; //good echo "</td><td>"; echo $row['description']; //good echo "</td><td>"; echo $row['in_return']; //good echo "</td></td>"; echo '<img src="images/K_little.png">'; //the picture appears,, but not in table format like the rest of echo "</td></tr>"; //rows from mysql. All the info is in mysql, except for the K_little } echo "</table>"; ?> Will this be a problem getting the K_little to appear on the page in the format I would like. Right now the K_little echos above the table and not inside it like the data from mysql. The table will keep displaying students until no more are in the system. So the letter K_little.png picture needs to be displayed in the letter column of the table for each student,,,, Understand??? ------------------------------------------| |student description in return letter | | xxxxx xxxxx xxxx k | | xxxx xxxxx xxxxx k | | xxxxx xxxxx xxxxx k Link to comment https://forums.phpfreaks.com/topic/152564-solved-get-pic/ Share on other sites More sharing options...
amonk Posted April 4, 2009 Share Posted April 4, 2009 Try this: <?php echo "<tr><td>"; echo '<img src="' . $row['imgpath'] . '" width="125" alt="" />'; //works good echo "</td><td>"; echo $row['student']; //good echo "</td><td>"; echo $row['description']; //good echo "</td><td>"; echo $row['in_return']; //good echo "</td></td>"; echo "<img src=\"images/K_little.png\">"; //the picture appears,, but not in table format like the rest of echo "</td></tr>"; //rows from mysql. All the info is in mysql, except for the K_little } echo "</table>"; ?> The backslashes make PHP ignore them as syntax, just output them. Link to comment https://forums.phpfreaks.com/topic/152564-solved-get-pic/#findComment-801291 Share on other sites More sharing options...
justAnoob Posted April 4, 2009 Author Share Posted April 4, 2009 K_little.png picture is still echoing above the table. Not in the user info column of my table. Link to comment https://forums.phpfreaks.com/topic/152564-solved-get-pic/#findComment-801390 Share on other sites More sharing options...
justAnoob Posted April 5, 2009 Author Share Posted April 5, 2009 K_little.png is just a picture on the server that I want to display, it does not have a image path in mysql. It is this line of code that I want it to display in. I can get it to display, but not in the format that I want. Here is what is does now. <?php echo "<img src=\"images/K_little.png\">"; ?> K K K column 1 column 2 column 3 column 4 xx xx xx xx xx xx xx xx xx this is how I would like it to be column 1 column 2 column 3 column 4 xx xx xx K xx xx xx K xx xx xx K Link to comment https://forums.phpfreaks.com/topic/152564-solved-get-pic/#findComment-801521 Share on other sites More sharing options...
gffg4574fghsDSGDGKJYM Posted April 5, 2009 Share Posted April 5, 2009 ... echo $row['in_return']; //good echo "</td></td>"; echo "<img src=\"images/K_little.png\">"; ... Closing 2 td instead of closing then opening a td Use : ... echo "</td><td>"; ... Next time try validate your html code before posting into a forums for help : http://validator.w3.org/ That kind of error is easly found by the validator Link to comment https://forums.phpfreaks.com/topic/152564-solved-get-pic/#findComment-801527 Share on other sites More sharing options...
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