[SOLVED] creating showing image?

[sandbudd]

This code works great with displaying the results in its own page _blank how can I make it just pop up without opening a new browser kinda like in a pop up window?

 

<?php
if(empty($row_Recordset1['map'])){
   //empty() returned true : so there is nothing
   echo 'Directions';
}else{
   //empty() returned false so it is NOT true that there is nothing
   //so we can print it out:
   echo '<a href="/images/map/' . $row_Recordset1['map'] . '"  target="_blank" class="style3">Directions</a>';
}
?>

[sandbudd]

I know this has to be done in javascript but every thing I have tried returns a blank window

[eiledon01]

This is more a Javascript issue.

 

Even if you use a javascript popup, it will still open in a new window if you have target="_blank" in your link.

change

echo '<a href="/images/map/' . $row_Recordset1['map'] . '"  target="_blank" class="style3">Directions</a>';

to something like

echo '<a href="javascript://" onClick="popupfunction(\'/images/map/' . $row_Recordset1['map'] . '\');"   class="style3">Directions</a>';

where "popupfunction" is a Javascript function that launches a popup.

[sandbudd]

when link is clicked nothing happens?

[eiledon01]

You need a javascript popup function:

http://www.google.com/search?q=javascript+popup+function+tutorial&meta=

[sandbudd]

oh well javascript is something I know nothing about