jamesxg1 Posted April 10, 2009 Share Posted April 10, 2009 <?php function CheckFolder() { $userid = $_SESSION['userid'] if(!file_exists(../User_Files/$userid)) die("FileGenPrimary(); FileGenImages(); FileGenVideos(); FileGenDocs();"); } ?> Parse error: syntax error, unexpected T_IF in C:\xampp\htdocs\family\Database\Utility.php on line 224 Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/ Share on other sites More sharing options...
taquitosensei Posted April 10, 2009 Share Posted April 10, 2009 you're missing a ; <?php function CheckFolder() { $userid = $_SESSION['userid']; // right here you're missing this ; if(!file_exists(../User_Files/$userid)) die("FileGenPrimary(); FileGenImages(); FileGenVideos(); FileGenDocs();"); } ?> a lot of times the the error is actually before the line number reported. Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/#findComment-806674 Share on other sites More sharing options...
jamesxg1 Posted April 10, 2009 Author Share Posted April 10, 2009 good eye you have there and code changed. . . <?php function CheckFolder() { $userid = $_SESSION['userid']; if(!file_exists(../User_Files/"$userid") { die("FileGenPrimary(); FileGenImages(); FileGenVideos(); FileGenDocs();"); } } ?> Parse error: syntax error, unexpected '.', expecting ')' in C:\xampp\htdocs\family\Database\Utility.php on line 214 Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/#findComment-806678 Share on other sites More sharing options...
Yesideez Posted April 10, 2009 Share Posted April 10, 2009 if(!file_exists("../User_Files/".$userid)) { One close bracket was missing and quotes in the wrong place. Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/#findComment-806682 Share on other sites More sharing options...
jamesxg1 Posted April 10, 2009 Author Share Posted April 10, 2009 if(!file_exists("../User_Files/".$userid)) { One close bracket was missing and quotes in the wrong place. gosh, my coding standards are going down hill lol!!, change of code <?php function CheckFolder() { $userid = $_SESSION['userid']; if(!file_exists(../User_Files/"$userid")) { die("FileGenPrimary(); FileGenImages(); FileGenVideos(); FileGenDocs();"); } } ?> Parse error: syntax error, unexpected '.', expecting ')' in C:\xampp\htdocs\family\Database\Utility.php on line 214 Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/#findComment-806685 Share on other sites More sharing options...
jamesxg1 Posted April 10, 2009 Author Share Posted April 10, 2009 got it working , Thanks for your time guys Link to comment https://forums.phpfreaks.com/topic/153526-solved-if-statement-in-function-not-working-help/#findComment-806691 Share on other sites More sharing options...
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