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[SOLVED] IF statement in function not working help


jamesxg1

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<?php
function CheckFolder() {

$userid = $_SESSION['userid']

if(!file_exists(../User_Files/$userid))
die("FileGenPrimary();
FileGenImages();
FileGenVideos();
FileGenDocs();");
   }

?>

 

Parse error: syntax error, unexpected T_IF in C:\xampp\htdocs\family\Database\Utility.php on line 224

you're missing a ;

<?php
function CheckFolder() {

$userid = $_SESSION['userid'];   // right here you're missing this ; 

if(!file_exists(../User_Files/$userid))
die("FileGenPrimary();
FileGenImages();
FileGenVideos();
FileGenDocs();");
   }

?>

a lot of times the the error is actually before the line number reported.

good eye you have there ;)

 

and code changed. . .

 

<?php
function CheckFolder() {

$userid = $_SESSION['userid'];   

if(!file_exists(../User_Files/"$userid") {
die("FileGenPrimary();
FileGenImages();
FileGenVideos();
FileGenDocs();");
   }
}
?>

 

Parse error: syntax error, unexpected '.', expecting ')' in C:\xampp\htdocs\family\Database\Utility.php on line 214

if(!file_exists("../User_Files/".$userid)) {

 

One close bracket was missing and quotes in the wrong place.

 

gosh, my coding standards are going down hill lol!!,

 

change of code

 

<?php
function CheckFolder() {

$userid = $_SESSION['userid'];   

if(!file_exists(../User_Files/"$userid")) {
die("FileGenPrimary();
FileGenImages();
FileGenVideos();
FileGenDocs();");
   }
}
?>

 

 

Parse error: syntax error, unexpected '.', expecting ')' in C:\xampp\htdocs\family\Database\Utility.php on line 214

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