[SOLVED] printf question

[sKunKbad]

If I have a variable that holds some text:

 

$output = "<p>";

 

and then want to add to that variable with printf

 

$output .= printf(....);

 

then print:

 

print $output;

 

it doesn't work. it prints what is inside printf before what was in $output, and what was in printf is not in $output. Is what I want to do possible? I'm really just adding a string to a string.

[PFMaBiSmAd]

That's because printf(....) sends the output to the browser, like it states in the php manual.

 

You want sprintf(....)

[sKunKbad]

Hey, thanks! I'm not up to speed on my printf and sprintf. I appreciate your quick answer.