palanikumark Posted April 22, 2009 Share Posted April 22, 2009 Actually here i'm passing xml as string. If I pass as xml it works fine. It does not working if I pass xml as string i'm receiving error Problem retrieving data. What should I change to work fine. Here is my code. var xmlString="<?xml version='1.0'?><note> <to>Tove</to> <from>Jani</from> <heading>Reminder</heading> <body>Dont forget me this weekend!</body> </note>"; # createXmlObject = function(xmlString) { # var xmlhttp; # xmlhttp=null; # if (window.XMLHttpRequest) # {// code for Firefox, Opera, IE7, etc. # alert("safari"); # xmlhttp=new XMLHttpRequest(); # xmlhttp.overrideMimeType('text/xml'); # } # else if (window.ActiveXObject) # {// code for IE6, IE5 # xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); # } # if (xmlhttp!=null) # { # xmlhttp.onreadystatechange=stateChange; # xmlhttp.open("GET",xmlString,true); # xmlhttp.send(null); # # } # else # { # alert("Your browser does not support XMLHTTP."); # } # } # # function stateChange() # { # if (xmlhttp.readyState==4) # {// 4 = "loaded" # if (xmlhttp.status==200) # {// 200 = "OK" # document.getElementById('to').innerHTML=xmlhttp.status; # document.getElementById('from').innerHTML=xmlhttp.statusText; # document.getElementById('heading').innerHTML=xmlhttp.responseText; # } # else # { # alert("Problem retrieving data:" + xmlhttp.statusText); # } # } # } Thanks Link to comment https://forums.phpfreaks.com/topic/155155-parsing-details-from-xml-string/ Share on other sites More sharing options...
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