joining variable with string name

[nuttycoder]

this should be simple but can't seem to see it.

 

I need to join a variable name and a string into a single variable for str_replace to work

 

I have variables been included by including files and I want to do a string replace that replaced the contents of [$plugin] with the contents of $output, in the external file I have my veribles like $blogOutput.

 

So when referencing them I need to get the 'blog' bit which I can that's inside $plugin and also need to add 'Output' to the end of it in such as way that php still knows its a varible coming from the included file.

 

Tried a few ways nothing working as yet here's my latest attempt:

 

       $plugin_file = "plugins/$plugin/$plugin.php";
include($plugin_file);

$output = $plugin . 'Output';

$string = str_replace("[$plugin]", $output, $string);

 

Can some one give me a slap and tell me what am doing wrong...

 

[mattal999]

*slap*.

 

Post the code of your included file, with the variable names please.

[nuttycoder]

this is from the included file just just one var as a test

 

<?php
$blogOutput = "FROM THE BLOG";
?>

[mattal999]

Well, currently, that script is trying to replace this:

 

Find the text '[$plugin]' with '$output' in the variable $string.

 

The variable $string is blank. Do you mean to replace the string $blogOutput?

[mikesta707]

Ok I dont quite Understand you but let me see if I got this straight. You want to take a string, and replace every occurence of the sub string [$plugin] with the variable output? tha seems easy enough

 

$output = $plugin."Output";//this is what you want to do right?
$plugin = "[".$plugin."]";//this is what plugin should be right? what you want to replace?

$string = str_replace($plugin, $output, $string);

 

try that. I hope that helps. It is kind of difficult to understand what you are trying to do

[nuttycoder]

thanks for the reply guys think my post wasn't very clear let me try and explain it a bit better

 

I have 2 files one called sample.php and one called blog,php that get included inside a function that is passed a block of text I want every reference of say [blog] to be replaced with $blogOutput and the same for [sample] and $sampleOutput

 

<?php
function outputPageCont($string)
{
$plugins = array('sample','blog'); 

foreach ($plugins as $plugin)
{

$plugin_file = "plugins/$plugin/$plugin.php";
include($plugin_file);

        $output = $plugin . 'Output';

$string = str_replace("[$plugin]", $output , $string);

}	
echo $string;
}

 

 

here's the two files first blog.php:

 

<?php
$blogOutput = "FROM THE BLOG";
?>

 

and sample.php:

<?php
$sample = 'I come from the sample plugin';
?>

 

If I hand coded the names manually it would work put I'd like to do it dynamically

 

<?php
$string = str_replace("[$plugin]", $blogOutput, $string);
$string = str_replace("[$plugin]", $sampleOutput, $string);
?>

[nuttycoder]

anyone any ideas?

 

 

$plugin contains all the plugins like: blog,sample

 

I need to go from

 

$string = str_replace("[$plugin]", $blogOutput, $string);
$string = str_replace("[$plugin]", $sampleOutput, $string);

 

to

 

$string = str_replace("[$plugin]", $someOutputCode, $string);