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[SOLVED] Is it possible to insert values into a single column?


seany02

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i want to insert values into a single column of a a table. ive attempted it with this;

<?php


$db = @mysql_connect("localhost","root","");

if (!$db)
{
do_error("Could not connect to the server");
}

// Connect to the database
@mysql_select_db("Rufus" ,$db)or do_error("Could not connect to the database");
// Run query
$name=$_POST["secondtxt"];
$name2=$_POST["thirdtxt"]; 
$result = mysql_query("INSERT INTO project WHERE project_id='$name' (user_id)
					VALUE ('$name2)",$db);
?>

 

however the column doesnt appear changed in the database.

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i changed my code to this, it didnt work. anything else you can do for me?

<?php


$db = @mysql_connect("localhost","root","");
$sql = "UPDATE project SET user_id='$name2' WHERE project_id='$name'";
if (!$db)
{
do_error("Could not connect to the server");
}

// Connect to the database
@mysql_select_db("Rufus" ,$db)or do_error("Could not connect to the database");
// Run query
$name=$_POST["secondtxt"];
$name2=$_POST["thirdtxt"]; 
$result = mysql_query("$sql,VALUE ('$name2)",$db);
?>

 

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and i tried this

<?php


$db = @mysql_connect("localhost","root","");
$sql = mysql_query;
if (!$db)
{
do_error("Could not connect to the server");
}

// Connect to the database
@mysql_select_db("Rufus" ,$db)or do_error("Could not connect to the database");
// Run query
$name=$_POST["secondtxt"];
$name2=$_POST["thirdtxt"]; 
$sql = "UPDATE project SET user_id='$name2' WHERE project_id='$name'";
?>

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I think this is what you mean. but i now get this error in the browser

ERROR!

Query:

Query was empty

 

<?php
$db = @mysql_connect("localhost","root","");

if (!$db)
{
do_error("Could not connect to the server");
}

// Connect to the database
@mysql_select_db("Rufus" ,$db)or do_error("Could not connect to the database");
// Run query
$name=$_POST["secondtxt"];
$name2=$_POST["thirdtxt"]; 
mysql_query($sql, $db) or die('ERROR!<br />Query: '.$sql.'<br />'.mysql_error());
$sql = "UPDATE project SET user_id='$name2' WHERE project_id='$name'";
?>

 

i do appreciate your help alot, i know im very difficult sometimes

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thanks it does work. the post with the hyperlink in wasnt very clear, maybe its my eyes only been working on the site for 12 hours. perhaps it would have been easier to say swap the lines over, not imply that i dont understand the syntax. i did memtion i was php inept earlier, and wouldnt be on this forum if i did.

thanks again, especially for your time.

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