NathanLedet Posted April 27, 2009 Share Posted April 27, 2009 I'm building a little animal management system where people can update records of animals they keep. I have given the ability to upload an image - and when a user edits an animal, and chooses NOT to upload a new image, then the image initially chosen will not change. So, in my code to process the submission, I have the following SQL query that is running into an unexpected T_IF. $sql = "UPDATE rcms SET `animal_id` = '{$animalid}', `type` = '{$animaltype}', `weight` = '{$animalweight}', `birthday` = '{$animalbday}', `description` = '{$animaldescription}'" . if ($filename != NULL){ ", `image` = '{$filename}'" }. "WHERE id='{$id}' LIMIT 1"; I have other code that process the image if it's there, or sets the $filename variable to NULL if the file field is left blank. So, essentially, All I'm trying to do is say if $filename is not NULL (has a name of a new file) - add that snippet of code so that it will update in the database. Link to comment https://forums.phpfreaks.com/topic/155866-building-a-sql-query-unexpected-t_if/ Share on other sites More sharing options...
Mchl Posted April 27, 2009 Share Posted April 27, 2009 You can't use concatenation like this. Try: $sql = "UPDATE rcms SET `animal_id` = '{$animalid}', `type` = '{$animaltype}', `weight` = '{$animalweight}', `birthday` = '{$animalbday}', `description` = '{$animaldescription}'" .(($filename != NULL) ? ", `image` = '{$filename}'" : ""). "WHERE id='{$id}' LIMIT 1"; Link to comment https://forums.phpfreaks.com/topic/155866-building-a-sql-query-unexpected-t_if/#findComment-820385 Share on other sites More sharing options...
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