crazzypappy Posted April 28, 2009 Share Posted April 28, 2009 Ok heres what i want to do i have a race script and would like to work out the chances of beating each person car speed vs car speed , the script give mph for both users i have worked out how to show a percentage but sometimes its showing 200 % so i want to do is create an if - elseif to limit the percentage shown as 100% this is what i have got so far but it is giving me errors else { if ( $_GET['race'] ) { $racer = $_GET['race']; if ( $racer == 'chris' ) { $fuel = rand(5,12); $raced = "Chris"; $speeds = "20"; $ra = "1"; $percent = mph/$speeds*100; $Percent2 = $percent; $nextrace = time()+120; $reps = rand(500,1200); $mns = rand(200,1500); //this is the section im having trouble with $percent3 = (if ($percent >= 100){ echo "100" } elseif ($percent < 100){ echo $Percent2}) } elseif ( $racer == 'jon' ) { Thanks for any help you can offer Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/ Share on other sites More sharing options...
Cosizzle Posted April 28, 2009 Share Posted April 28, 2009 im confused why you have an if inside a variable. should'nt need to be. try <?php if ($percent >= 100) { echo "100"; } else if ($percent < 100) { echo $Percent2; } ?> or (not sure what your trying to accomplish but... <?php if ($percent >= 100) { $percent3 = 100; } else if ($percent < 100) { $percent3 = $Percent2; } ?> Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-821200 Share on other sites More sharing options...
Zhadus Posted April 28, 2009 Share Posted April 28, 2009 A little cleaner version of Cosizzle's response: <?php $percent3 = ($percent >= 100) ? 100 : $Percent2; ?> By the way, what's the reason for having $percent, $Percent2, and $percent3? Reuse variables if you can. Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-821259 Share on other sites More sharing options...
nogginj Posted April 28, 2009 Share Posted April 28, 2009 also: $percent = mph/$speeds*100; should probably be $mph? Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-821264 Share on other sites More sharing options...
crazzypappy Posted April 28, 2009 Author Share Posted April 28, 2009 no the mph comes from a sql table the original script that does give a result is if ( $racer == 'chris' ) { $fuel = rand(5,12); $raced = "Chris"; $speeds = "20"; $ra = "1"; $percent = mph/$speeds*100; $nextrace = time()+120; $reps = rand(500,1200); $mns = rand(200,1500); } but what happens is if mph is like 300 it would give me a result larger than 100 % and i want to limit the ansver no greater than 100 Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-821414 Share on other sites More sharing options...
Zhadus Posted April 30, 2009 Share Posted April 30, 2009 If mph comes from a MySQL table, you need to assign the value to a PHP variable otherwise it doesn't know what "mph" stands for. Once you do that, the code I provided will work. Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-822908 Share on other sites More sharing options...
crazzypappy Posted May 1, 2009 Author Share Posted May 1, 2009 Sorry for the delay in replying back , been working :-( anyways yep that fixed it thanks for your help. Link to comment https://forums.phpfreaks.com/topic/155999-solved-if-statment-inside-an-if-statment/#findComment-823276 Share on other sites More sharing options...
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