[SOLVED] if no photo is present error

[busnut]

G'day

 

I downloaded this snippet from the net that it searches a designated directory (which in my case depends on what the user has searched for), and if there is no photo, it just displays the img holder, but no image.

 

How can I get it that if there are no images in that directory, that it could display a default image like 'no image yet' or even just text of the same wording?

 

here is the code:

$dir = "photos/".$result['chassisbody']; // The directory where your images are
$filetypes = ("jpg"||"gif"); // Whatever images are valid. You could add “png” etc

srand((double)microtime()*123456789); // Generates a random number seed
$count = 0; // Initialises the counter

$dirOpen = opendir($dir); // Opens the image directory

while(($im = readdir($dirOpen)))
{
if($im != ".." && $im != "." && substr($im,-3)==$filetypes) // Disregards ".." and "." (direcrory structure)
{
$image[$count] = $im; // Reads an image
$count++; // Increments the counter
}
}

closedir($dirOpen); // Closes the directory

$randname = rand(0,(count($image)-1)); // Generates the random number
//echo "<img src='".$dir."/".$image[$randname]."' width='300'>"; // Publishes the image

[Ken2k7]

substr($im,-3)==$filetypes

Can you do checking like that in PHP? I didn't know that. Hmm...

[busnut]

substr($im,-3)==$filetypes

Can you do checking like that in PHP? I didn't know that. Hmm...

Must be able to. The script works perfect, and does what it should, just can't work out that if no image present, echo this instead...

[PFMaBiSmAd]

The posted code creates an array of images in $image. You can use the empty function to test if the array is empty.

[Ken2k7]

Damn.. he beat me.

[busnut]

ok, this is what i've done (took me a little while though to work out what var should be), and so far works perfectly:

$dir = "photos/".$result['chassisbody']; // The directory where your images are
$filetypes = ("jpg"||"gif"); // Whatever images are valid. You could add “png” etc

srand((double)microtime()*123456789); // Generates a random number seed
$count = 0; // Initialises the counter

$dirOpen = opendir($dir); // Opens the image directory

while(($im = readdir($dirOpen)))
{
if($im != ".." && $im != "." && substr($im,-3)==$filetypes) // Disregards ".." and "." (direcrory structure)
{
$image[$count] = $im; // Reads an image
$count++; // Increments the counter
}
}

closedir($dirOpen); // Closes the directory

$randname = rand(0,(count($image)-1)); // Generates the random number

if (empty($count)) {
    echo "Sorry, no image currently available for this bus";}

else echo "<a href='".$dir."/".$image[$randname]."' rel=\"lightbox\" title=\"".$result['chassisbody']."\" border=1><img src='".$dir."/".$image[$randname]."' border=0 width=300></a>";

 

Thanks for teh help guys!