ArizonaJohn Posted May 12, 2009 Share Posted May 12, 2009 Hello, I would like to use the same variable on three pages. Right now I can only get it to work on two. The first page has a simple HTML form where the variable is entered. The second page uses the variable just fine. I am using AJAX to refer to a third page, and I'm not sure how to use the same variable on the third page. The variable is called "find." On the second page, I have this: $find = strip_tags($find); $find = trim ($find); $result=mysql_query("SHOW TABLES FROM sand2 LIKE '%$find%'") or die(mysql_error()); The second page then has AJAX which points to a third page/URL, and on this third page/URL, I have this: function getAllVotes($id) { /** Returns an array whose first element is votes_up and the second one is votes_down **/ $votes = array(); $q = "SELECT * FROM santafe WHERE id = $id"; On the third page, I would like to replace the table "santafe" with the variable "find," the same variable that I use on the second page. How do I do this? Thanks in advance, John Link to comment https://forums.phpfreaks.com/topic/157878-pushing-a-variable-through-to-a-third-page-while-using-ajax/ Share on other sites More sharing options...
Ken2k7 Posted May 12, 2009 Share Posted May 12, 2009 You want to replace a table with a variable? O_O Link to comment https://forums.phpfreaks.com/topic/157878-pushing-a-variable-through-to-a-third-page-while-using-ajax/#findComment-832780 Share on other sites More sharing options...
ArizonaJohn Posted May 12, 2009 Author Share Posted May 12, 2009 Well, I guess I should have said I want to make the table name a variable. On the second page, the table displayed is the one whose name matches the variable "find." I want to use this same table in the third page that the AJAX points to. Link to comment https://forums.phpfreaks.com/topic/157878-pushing-a-variable-through-to-a-third-page-while-using-ajax/#findComment-832788 Share on other sites More sharing options...
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