dh526 Posted May 19, 2009 Share Posted May 19, 2009 Right, this is my second message on here because I'm a beginner to php. It is very interesting though and last time people were VERY helpful This might be a very basic question but I'm not sure quite where I'm going wrong even though I kind of know it will be something silly I am doing wrong :S This question relates to cookies... I know how to set a cookie, with setcookie('username', $username) however I do not know how to set $username to be a value that is input by the user into a form. I am creating a login system for a website and this will make everything else fall into place (i hope) so any help would be much appreciated:) So i want to do something like this: User enters name into a text field in a form called 'username' the value of 'username' is stored in the cookie. then in another page this can be accessed and printed Thank you so so much for your help Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/ Share on other sites More sharing options...
rondog Posted May 19, 2009 Share Posted May 19, 2009 $username = $_POST['usernamefield'] ??? Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837689 Share on other sites More sharing options...
Masna Posted May 19, 2009 Share Posted May 19, 2009 firstpage.html <form action="secondpage.php" method="post"> <input type="text" name="username"> <input type="submit" name="submit" value="Login"> <form> secondpage.php $username = $_POST['username']; Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837691 Share on other sites More sharing options...
Brian W Posted May 19, 2009 Share Posted May 19, 2009 Look into this quick, easy, well done tutorial: here Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837692 Share on other sites More sharing options...
cringe Posted May 19, 2009 Share Posted May 19, 2009 I'm free-handing this so the syntax might be wrong but... $safe_name = '' ; if ( isset($_COOKIE['username'] ) $safe_name = htmlentities($_COOKIE['username'], ENT_QUOTES) ; echo '<input type="text" name="username" value="', $safe_name, '" />'; CR Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837697 Share on other sites More sharing options...
dh526 Posted May 19, 2009 Author Share Posted May 19, 2009 Thank you Still not 100% done though... I have login.html <html> <head> </head> <body> Please login <br> <form method="post" action="login1.php"> username:<input type="text" name= "username"/> <br> <input type="submit" /> </form> </body> </html> and login1.php <html> <head> </head> <body> <? $username = $_POST ['username']; setcookie('username', $username); echo "<a href="login2.php">LINK</a>"; ?> </body> </html> and then i want to show the username in another page, called login2.php <? echo $_COOKIE['username']; ?> again, I don't know why this isn't working :S Sorry, I feel such a plonker while doing this sometimes ... Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837704 Share on other sites More sharing options...
cringe Posted May 20, 2009 Share Posted May 20, 2009 login1.php <?php $username = $_POST ['username']; setcookie('username', $username); ?> <html> <head> </head> <body> <?php echo "<a href="login2.php">LINK</a>"; ?> </body> </html> HTTP headers must be sent BEFORE any HTML (body of the response). And a cookie is a header. I moved your setcookie up in the code. You can also use ob_start output buffering to get around this restriction. http://us3.php.net/manual/en/function.ob-start.php . And you could instead store the value $_SESSION and it would be available in login2.php. CR Link to comment https://forums.phpfreaks.com/topic/158827-cookies-and-php/#findComment-837775 Share on other sites More sharing options...
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