preg_replace and <ul>

[immanuelx2]

Hey all. I have been trying to figure this out for literally several hours and my head is starting to hurt. I come to you experts as a last resort.  I am by no means a regexp expert, in fact the format below is something I snagged off the internet, so it may be wrong...

 

So far I have this for my bbcode parsing:

<?php

$bbcode = array(
	'@\[url=(.*?)\](.*?)\[/url\]@si' => '<a href="\\1" target="_blank">\\2</a>',
	'@\[quote\](.*?)\[/quote\]@si' => '<i>"\\1"</i>',
	'@\[ul\](.*?)\[/ul\]@si' => '<ul>\\1</ul>' ,
	'@\[li\](.*?)\[/li\]@si' => '<li>\\1</li>' 
);

return preg_replace(array_keys($bbcode), array_values($bbcode), $string);

?>

 

However, when it comes to the "ul" and "li" tags... I want to omit any newline ("\n") characters before or after those elements, because I have a nl2br() statement that parses right at the end to output the HTML, and since <li> tags are naturally list-type elements, they don't need extra <br /> around them.

 

Just like in these forums:

[list]
[*]item 1
[*]item 2
[/list]

 

between items 1 and 2, and the two list tags, no additional line breaks are added, even though there are newlines created when that code is written. So my question is, how can I remove the newlines at those specific points only, so that my nl2br() can parse the rest of the newlines in my string as breaks?

 

Thanks in advance for any help

[Ken2k7]

You can use \s

 

And m modifier for multiple lines.

[immanuelx2]

You can use \s

 

And m modifier for multiple lines.

 

Could you elaborate? Sorry I'm a newb when it comes to regexp... Could you maybe give me an example of what you mean?

[immanuelx2]

bump

[immanuelx2]

anyone?