justAnoob Posted May 23, 2009 Share Posted May 23, 2009 <?php if( (empty($row['imgpath4'])) and (!empty($row['imgpath3'])) and (!empty($row['imgpath2'])) ) ?> Can't seem to make this work...I'm sure I'm doing this wrong..Is there another way? Quote Link to comment Share on other sites More sharing options...
anupamsaha Posted May 23, 2009 Share Posted May 23, 2009 <?php if( (empty($row['imgpath4'])) and (!empty($row['imgpath3'])) and (!empty($row['imgpath2'])) ) ?> Can't seem to make this work...I'm sure I'm doing this wrong..Is there another way? Can you provide some more information here that what are you trying to do and if any error you are encountering? Quote Link to comment Share on other sites More sharing options...
Ken2k7 Posted May 23, 2009 Share Posted May 23, 2009 Nothing wrong syntactically unless you meant !empty($row['imgpath4']). Quote Link to comment Share on other sites More sharing options...
cunoodle2 Posted May 23, 2009 Share Posted May 23, 2009 <?php if( (empty($row['imgpath4'])) and (!empty($row['imgpath3'])) and (!empty($row['imgpath2'])) ) ?> IF path4 IS empty, path3 is NOT empty and path2 is NOT empty Then..do the stuff. If ANY of the above are not true then the If statement will be false. Is that what you want the statement to say/do? Quote Link to comment Share on other sites More sharing options...
justAnoob Posted May 23, 2009 Author Share Posted May 23, 2009 sorry guys,, the line was correct,, a different line had an error... my bad... Quote Link to comment Share on other sites More sharing options...
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