JamesXL1967 Posted May 23, 2009 Share Posted May 23, 2009 Hi Guys I am new to PHP and mysql and I wondered if anyone could explain this error : Call to undefined function: resource id #88() in mydomain/home/myfile.php on line 63 The code it relates to is as follows (line 63 highlighted) : $user_data = $db->query("SELECT user_hi, user_lo FROM " . DB_PREFIX . "users WHERE user_id='" . $session->value('user_id') . "'"); $sql_select_data = $db->query("SELECT a.item_id, a.name, a.price, a.currency, a.owner_id, a.item_hi, a.item_lo, LINE 63 >>> sqrt (((". $user_data($user_hi) ." - a.item_hi)*( ". $user_data($user_hi) . " -a.item_hi)) + ((".$user_data($user_lo)." - a.item_lo)*(".$user_data($user_lo)." - a.item_lo))) AS TDifference FROM " . DB_PREFIX . "items a " . $force_index . " " . $where_query . " GROUP BY a.item_id ORDER BY TDifference ASC LIMIT " . $start . ", " . $limit); } Any help with the above or if you can spot any other errors in the code would be appreciated. Many thanks in advance Link to comment https://forums.phpfreaks.com/topic/159402-solved-please-help-error-message/ Share on other sites More sharing options...
wildteen88 Posted May 23, 2009 Share Posted May 23, 2009 Judging by your code I think $user_data($user_hi) should of been $user_data['user_hi'] and $user_data($user_lo) should of been $user_data['user_lo'] Link to comment https://forums.phpfreaks.com/topic/159402-solved-please-help-error-message/#findComment-840818 Share on other sites More sharing options...
JamesXL1967 Posted May 23, 2009 Author Share Posted May 23, 2009 Many thanks for the prompt reply Wildteen I will give that a try. Link to comment https://forums.phpfreaks.com/topic/159402-solved-please-help-error-message/#findComment-840827 Share on other sites More sharing options...
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