How do i detect a capital letter in a sentence

[receiver19]

Let's say I have a string  "GetToKnowYou".

 

I wish to search the upper capital of that string and separate them into "Get To Know You"

 

Any idea?

 

Thanks in advanced.

[BobcatM]

<?php 

$string = $_GET['string']; 

$count = strlen($string); 

$i = 0; 
$ii = 0; 

while($i < $count) 
{ 
        $char = $string{$i}; 
        if(ereg("[A-Z]", $char, $val)){ 
                $ii++; 
                $strings[$ii] .= $char; 
        } else { 
                $strings[$ii] .= $char; 
        } 
$i++; 
} 

var_dump($strings); 

?>

[BobcatM]

<?
$str="GetToKnowYou";

preg_match_all('/[A-Z][^A-Z]*/',$str,$results);

?>

 

Or an easier way.

[Ken2k7]

<?php
$str = 'GetToKnowYou';
$new_str = rtrim(preg_replace('#([A-Z][^A-Z]*)#', '$1 ', $str));
var_dump($new_str);

[receiver19]

Thanks for all the replied.

 

<?php
$str = 'GetToKnowYou';
$new_str = rtrim(preg_replace('#([A-Z][^A-Z]*)#', '$1 ', $str));
var_dump($new_str);

 

This works very well! However, i don't get it on this part ('#([A-Z][^A-Z]*)#', '$1 ', . I still don't understand though i have read the php manual. Anyone mind to explain to me?

[receiver19]

<?
$str="GetToKnowYou";

preg_match_all('/[A-Z][^A-Z]*/',$str,$results);

?>

 

Or an easier way.

 

BobcatM, i have tried this one. However, when i echo it out. The results isn't right, any idea on it?

[Wuhtzu]

The preg_replace() function searches through a string matching the whole thing or parts of it to a regular expression pattern.

 

In this case the the pattern '#([A-Z][^A-Z]*)#' means match a string starting with one capital letter followed by any number of characters not matching a capital letter.

 

#: a delimiter marking the start of the actual regular expression pattern

(: start of a capture group

[A-Z]: a character class matching one character in the range A-Z

[^A-Z]*: a character class matching one character not in the range A-Z (that could be a, b, c, 12, #, [ ect.) and actually any number of them (including zero) because of the modifier *

): end of capture group

#: a delimiter marking the end of the actual regular expression pattern

 

Now the syntax of the preg_replace() is: preg_replace($regular_expression, $what_to_replace_with, $string_to_search_and_replace). The search is done with the previous mentioned pattern and we are using '$1 ' as the replacement. $1 means the first capture group or sub pattern - what's inside the parentheses - it's called a back reference. So each time the regex engine matches the previously discussed pattern it assign it's value to $1 and '$1 ' of course adds a space.

 

So going through this string 'GetToKnowYou' will first match 'Get' ([A-Z] followed by two [^A-Z]) and assign it's value to $1. So 'Get' is replaced with 'Get '. Now it matches 'To' and replaces it with 'To ' and so on. So in the end it's 'Get To Know You'.

 

Read more on regular expression here: http://www.regular-expressions.info/, http://www.regular-expressions.info/tutorial.html, http://www.regular-expressions.info/reference.html

 

 

 

 

[receiver19]

Very well explanation. I have clearer understanding. Thanks a lot!!

 

 

And, thanks to everyone reply to post. I really appreciate your all kindly help.