[SOLVED] Variables/preg_replace

[SoberDude]

I need to use a variable in a preg_replace, like:

 

$blah= preg_replace('$variable', 'blah', $blah);

 

If I try to use a variable in the search part of preg_replace, it does not work.

[lonewolf217]

why do you have quotes around the variable ?  it would be trying to literally use $variable as the regular expression to match it to.

 

see the example here http://us.php.net/preg_replace

 

If you still dont get it, we need specific code examples, not "blah blah something like this" to find the issue

[SoberDude]

why do you have quotes around the variable ?  it would be trying to literally use $variable as the regular expression to match it to.

 

see the example here http://us.php.net/preg_replace

 

If you still dont get it, we need specific code examples, not "blah blah something like this" to find the issue

I know, I was just using the variable as an example. I know it is an incorrect syntax.

 

The actual one is more like:

 

$newvar = preg_replace_callback('/' . $var . '([^\b\(]*.)/', "remove_caps", $newvar);

[SoberDude]

Oh wait, nevermind. Apparently my variable had a "(" in it.