Jump to content

[SOLVED] Send a variable to a function from an echo statement


grs5211

Recommended Posts

I want to send a variable concatenated with some text to a javascript function.

 

Clearly this will work.

echo "<SCRIPT LANGUAGE='javascript'>errorMessages('This is not a valid ID);</SCRIPT>";

 

However I want to do this:

echo "<SCRIPT LANGUAGE='javascript'>errorMessages($_REQUEST["UserID"] + '  is not a valid ID);</SCRIPT>";

 

Any ideas?

Link to comment
Share on other sites

I want to send a variable concatenated with some text to a javascript function.

 

Clearly this will work.

echo "<SCRIPT LANGUAGE='javascript'>errorMessages('This is not a valid ID);</SCRIPT>";

 

However I want to do this:

echo "<SCRIPT LANGUAGE='javascript'>errorMessages($_REQUEST["UserID"] + '  is not a valid ID);</SCRIPT>";

 

Any ideas?

 

Sure. Do this:

 

echo "<SCRIPT LANGUAGE='javascript'>errorMessages(<?php echo $_REQUEST["UserID"]?> + '  is not a valid ID);</SCRIPT>";

 

Link to comment
Share on other sites

Hmm... this is a hard one. :-\ Looks like you sort of solved it, but had a brain freeze. :P

 

echo "<SCRIPT LANGUAGE='javascript'>errorMessages('{$_REQUEST["UserID"]} is not a valid ID');</SCRIPT>";

Just put in the quotes correctly with some PHP variable interpolation syntax.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.