[SOLVED] Problem Coverting radians to degrees using sin.

[papaScott]

ok, so wheres what i have.

 

$Angle = $_POST['txtAngle'];

  $SinAngle = rad2deg(sin((float)$Angle));

echo $SinAngle;

which is:

-56.610042086.

I know that the the sin() function returns a value in radians. i need that in degrees.  Shouldn't this work? I've checked my calc and it gives me 0.5 as the sine of 30.(sin(30)).

 

can someone please help?

[papaScott]

Never mind, i found my problem.

it should be

$sinAngle = sin(deg2rad($angle));