Walker33 Posted June 9, 2009 Share Posted June 9, 2009 Hello. I'm trying to echo a single value from an array. Below displays all within a while loop, but what if I only want to display, say, the fourth value of the array? Sorry, this seems so simple, but I just can't seem to find the right answer anywhere. <?php $scoquery = mysql_query ("SELECT FirstName, LastName FROM customer_details WHERE License_Num like '3RF6%' "); while ($scoarray = mysql_fetch_array($scoquery)){ $scofirst = $scoarray['FirstName']; $scolast = $scoarray['LastName']; $scolics = $scofirst." ".$scolast; echo "$scolics<br><br>"; } ?> Always appreciate the help! Quote Link to comment https://forums.phpfreaks.com/topic/161583-display-single-value-from-array/ Share on other sites More sharing options...
Julian Posted June 9, 2009 Share Posted June 9, 2009 in_array() or array_search() should be what you need. Quote Link to comment https://forums.phpfreaks.com/topic/161583-display-single-value-from-array/#findComment-852666 Share on other sites More sharing options...
Walker33 Posted June 9, 2009 Author Share Posted June 9, 2009 hmm, looked at both those. Couldn't figure how to use them. in_array(search,array,type) where search specifies what to look for....could be anything. array_search seems to ask the same thing, meaning I pre-define what I'm searching for. Maybe I'm just misunderstanding, though. Quote Link to comment https://forums.phpfreaks.com/topic/161583-display-single-value-from-array/#findComment-852672 Share on other sites More sharing options...
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