[SOLVED] addition issue on alphanumeric value

[Walker33]

I have a three digit alphanumeric value that I'm adding 1 to, for instance S07.  My code works fine for all situations except 09, 19, 29, etc.  For instance, S09 becomes S010 instead of what I want, which is S10, S19 becomes S110 instead of S20, etc.  Not sure what to do, and I also need to avoid S11 becoming S22, S22 becoming S33, etc.

 

<?php
//$res is S09 in this case
$number = (int) $res[2];
$new_number = $number+1;
$reso = substr_replace($res, $new_number, 2);
//$reso becomes S010 instead of S10

?>

 

Really appreciate any help!

[MadTechie]

do you mean something like this

<?php
$res = "S19";
//$res = substr($res,0,1).(substr($res,1)+1);
$res = substr($res,0,1).sprintf('%02s', (substr($res,1)+1)); //Updated
echo $res;
?>

that works with 1 letter then 2 numbers

 

 

if you need something my complex ie unknown number of letter followed by 1 or more numbers then this maybe better

<?php
$res = "Something19";
if (preg_match('/([a-z]*)(\d+)/i', $res,$match)) {
//$res = $match[1].($match[2]+1);
$res = $match[1].sprintf('%02s', $match[2]+1)); //Updated
}
echo $res;
?>

 

this will work with any letters follow by 1 or 2 numbers

 

EDIT: oops missed something

just updated to so 01 would become 02 instead of just 2

[Walker33]

It's always just one letter followed by two numbers.  The first code you gave me does work for the 09, 29, etc., issue.  However, it also changes S07 into S8 instead of what I need, which would be S08.  I always need it to be three digits.  Further thoughts?

[MadTechie]

someone didn't read my update 

<?php
$res = "S07";

$res = substr($res,0,1).sprintf('%02s', (substr($res,1)+1));
echo $res;
?>

 

S08

[Walker33]

Beautiful!  (and yes, I missed your update, sorry 'bout that)  Works like a champ.  Thanks a ton!

[MadTechie]

Can you click topic solved please (bottom left)