Mysql Link error...

[eaglelegend]

Hi, I am getting rather annoyed with this little bit of code as it is giving me an error, on my application on facebook... any ideas?

 

The code: it is meant to get the users that have recently viewed my application from the database then display their pictures on the app.

 

$sql = "SELECT * FROM usertable order by uid DESC limit 7";
$result = mysql_query($sql, $connection);
$num = @mysql_num_rows($result);
$i = 0;
print"<div align=center><b>Recent Visitors</b><br />";
while ($num > $i) { 

$uids = mysql_result($result, $i, "uid");
$scores = mysql_result($result, $i, "point");
$num_games = mysql_result($result, $i, "gameplayed");
s
?>
<fb:profile-pic uid="<?php echo $uids; ?>" size="square" linked="true" />

echo '<fb:tabs>';
echo '<fb:tab-item href='.$appCanvasUrl.' title="Arcade Site List" selected="true" />';
echo '<fb:tab-item href='.$appCanvasUrl.'invite.php title="Invite Friends" />';
echo '</fb:tabs>';
<?php
//$game = mysql_result($result,$i, "game");
$i++;
}

print"</div>";
?>

 

This is the error im getting

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in THE_CODE on line 18

[papaface]

$connection

is not defined anywhere.