HELPPHP Error with MySQL Query - NEWBIE!

[kagster]

Please can someone help?

 

I have set up this query but keep gettin this error

 

Warning: mysqli_error() expects parameter 1 to be mysqli, resource given in C:\wamp\www\KidsCorner\search_results.php on line 46

 

 

Query: SELECT t.BtName, a.AuthorName, p.PubName FROM author AS a INNER JOIN authorship AS i USING (AuthorId) INNER JOIN BookTitle AS t USING (BtId) INNER JOIN publisher AS p USING (PubId) WHERE a.AuthorName LIKE '%

Warning: mysqli_close() expects parameter 1 to be mysqli, resource given in C:\wamp\www\KidsCorner\search_results.php on line 50

 

I'm presuming there is something wrong with the way I have done my query, as it is not working

 

Below is my code for my search form:

 

<br>

 

      Please enter the title of the book you wish to search for:<br />

<br />

 

 

<form action="search_results.php" method="post" name="findBook" id="findBook" class="finderForm">

 

<p><label>Book title:</label><input type="text" name="BtName" value="<?echo $_POST["BtName"]?>" class="field" size="20" /></p>

 

<p><label>Author:</label><input type="text" name="AuthorName" value="<?echo $_POST["AuthorName"]?>" class="field" size="20"/></p>

 

<p><label>Publisher:</label><input type="text" name="PubName" value="<?echo $_POST["PubName"]?>" class="field" size="20"/></p>

 

<p class="btn"><input type="submit" name="submit" value="Search BookWormz.." /></p>

 

<input type="hidden" name="submitted" value="TRUE" />

 

</form>

 

<? if (isset($_POST['submitted'])) { // Check form has been Submitted IF

 

// If it has process the search:

include("search_results.php");

?>

 

<? } else { // If the form has not been submitted. ?>

 

HERE IS MY CODE FOR MY RESULTS PAGE:

 

<?php

$page_title = 'Search Library!';

include ('includes/header.html');

?>

 

 

 

<?php

 

$dbc = mysql_connect ("localhost", "root","mudder")  or die (mysql_error()); 

mysql_select_db ("childrens_library"); 

 

 

 

//$sql = mysql_query("select * from BookTitle where BtName like '%$searchterm%'");

$query = "SELECT t.BtName, a.AuthorName, p.PubName FROM author AS a INNER JOIN authorship AS i USING (AuthorId) INNER JOIN BookTitle AS t USING (BtId) INNER JOIN publisher AS p USING (PubId) WHERE a.AuthorName LIKE '%".$_POST["AuthorName"]."%' AND p.PubName LIKE '%".$_POST["PubName"]."%' AND t.BtName LIKE '%".$_POST["BtName"]."%'";

 

 

$row = @mysqli_query ($dbc, $query); // Run the query.

 

if ($row) { // If it ran OK, display the records.

 

// Table header.

echo '<table cellspacing="0" cellpadding="0">';

echo '<tr><td><b>Book Title</b></td>';

echo '<td><b>Author</b></td>';

echo '<td><b>Publisher</b></td></tr>';

 

// Fetch and print all the records:

while ($row = mysqli_fetch_array($row, MYSQLI_ASSOC)) {

echo '<tr><td>' . $row['BtName'] . '</td>';

echo '<td>' . $row['AuthorName'] . '</td>';

echo '<td>' . $row['PubName'] . '</td></tr>';

}

 

echo '</table>'; // Close the table.

 

mysqli_free_result ($row); // Free up the resources.

 

} else { // If it did not run OK.

 

// Public message:

echo '<p>The book(s) you were looking for cannot be found. We apologize for any inconvenience.<br /><br />';

 

// Debugging message:

echo mysqli_error($dbc) . '<br /><br />Query: ' . $query . '</p>';

 

} // End of if ($row) IF.

 

mysqli_close($dbc); // Close the database connection.

 

Please can someone tell me where I am going wrong?

 

Many thanks

 

Paul

[Ken2k7]

If you have a mysql connection, why are you using mysqli functions? Stick with one or the other, not both.