If variable = anything within an array?

[r00ttap]

How would I go about checking if a variable equals anything within an array.

 

For instances:

 

$array = ('2009-06-01', '2009-06-02', '2009-06-20', '2006-06-25');
$today = "2009-06-20";

if($today = $array) {
     echo "Today was found within the array";
}

 

I know that won't work but it's what I'm looking to accomplish.

 

Thanks!

[PFMaBiSmAd]

in_array

[r00ttap]

Thank you!

[RussellReal]

wow.. (..,..,..,..) sets an array?

[PFMaBiSmAd]

No (try it if you want), the first post was just pseudo code to illustrate what he wanted.

[RussellReal]

oh, lmao I was like WOW WHY DIDN'T I KNOW THAT!

[r00ttap]

Actually I'm going to ask another question that relates to this one. How does one set a while loop results as an array?

 

$dateSelect = "SELECT dates FROM dates_table";

cancelDates = array();
while($row=mysql_fetch_assoc($dateSelect)) 

 

I basically want the dates to be set as an array.

[akitchin]

are the dates being stored as a comma-delimited list, or are they listed individually in the dates_table?

[r00ttap]

Individually, linked by id.

[RussellReal]

$dates = array();

while ($r = mysql_fetch_assoc($dateSelect) ) {

  $dates[] = $r['dates'];

}

[r00ttap]

Okay, so if I wanted to check if a date was in that array I would use:

 

if(in_array("2009-06-19", $dates)) { 
$checked = "checked"; 
}

echo $checked;

 

Why am I receiving this:

 

Warning: in_array() [function.in-array]: Wrong datatype for second argument

[PFMaBiSmAd]

The error means that $dates was not an array at the time that statement was executed. Did you verify what was in $dates at that point in the code?