[SOLVED] Date Question

[will35010]

I have a question about DATE. I want to generate select options for the years going back 30 and forward 5 in php. How would I do this?

 

<?PHP for($i=date("Y"); $i<=date("Y")+2; $i++)
if($year == $i)
echo "<option value='$i' selected>$i</option>";
else
echo "<option value='$i'>$i</option>";
?>

[cunoodle2]

Something like this will do day and year.  It will NOT work for leap years and such but you get the idea...

 

<select size="1" name="day">
<?php

//write out all the options for 1-31 days
for ($day = 1; $day < 32; $day++)
{
	echo "\n\t <option ";
	if ($day_of_month == $day)
		echo "SELECTED ";
	echo "value\"=".$day."\">".$day."</option>";
}?>
</select>  
<select size="1" name="year">
<?php
for ($i = (date("Y") - 30); $i < (date("Y") + 2); $i++)
{
	echo "\n\t <option ";
	if ($year == $i)
		echo "SELECTED ";
	echo "value\"=".$i."\">".$i."</option>";
}
?>

[will35010]

Something like this will do day and year.  It will NOT work for leap years and such but you get the idea...

 

<select size="1" name="day">
<?php

//write out all the options for 1-31 days
for ($day = 1; $day < 32; $day++)
{
	echo "\n\t <option ";
	if ($day_of_month == $day)
		echo "SELECTED ";
	echo "value\"=".$day."\">".$day."</option>";
}?>
</select>  
<select size="1" name="year">
<?php
for ($i = (date("Y") - 30); $i < (date("Y") + 2); $i++)
{
	echo "\n\t <option ";
	if ($year == $i)
		echo "SELECTED ";
	echo "value\"=".$i."\">".$i."</option>";
}
?>

 

Thanks.