Calculating age in number of years and number of months

[sheikhmdirfan]

Hi,

 

 

I would like to know as to how i can calculate age of a person years and months.

e.g say a person's DOB is 25-02-2008.. then it should show his/her age as

1 year and 4 months taking into consideration the number of days of each month..

 

Since all months dont have equal number of days..

 

How can i calculate his age in terms of years and number of months..

 

 

Any help is highly appreciated..

 

Thanks in advance..

[Twister1004]

Have you tried starting on this? If you have post your code.

 

However, I would use the year it is now minus their birth year.

[sasa]

<?php
function my_old($dob, $now = false){
if (!$now) $now = date('d-m-Y');
$dob = explode('-', $dob);
$now = explode('-', $now);
$old = $now[2]*12+$now[1]-$dob[2]*12-$dob[1]-($dob[0]>$now[0] ? 1 : 0);
return array('year' => floor($old / 12), 'mnt' => $old % 12);
}
$x = my_old('29-4-2008', '29-4-2009');
print_r($x);
?>

[pacchiee]

Can you please add the number of days too?

 

Something like this : 2 Years 4 Months 12 Days

 

Thanks in Advance!

[sasa]

<?php
function my_old($dob, $now = false){
if (!$now) $now = date('d-m-Y');
$dob = explode('-', $dob);
$now = explode('-', $now);
$mnt = array(1 => 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
if (($now[2]%400 == 0) or ($now[2]%4==0 and $now[2]%100!=0)) $mnt[2]=29;
if($now[0] < $dob[0]){
	$now[0] += $mnt[$now[1]-1];
	$now[1]--;
}
if($now[1] < $dob[1]){
	$now[1] += 12;
	$now[2]--;
}
if($now[2] < $dob[2]) return false;
return  array('year' => $now[2] - $dob[2], 'mnt' => $now[1] - $dob[1], 'day' => $now[0] - $dob[0]);
}
$x = my_old('29-4-2008', '28-5-2009');
print_r($x);
?>