seany123 Posted June 29, 2009 Share Posted June 29, 2009 okay so basically im making this page show images from a database... <div id="left_c"><div class="g_content"><h3> Your Points</h3><div class="g_text"><table width='100%' align='center' cellspacing='10'><tr> <td></td> <td></td> <td></td> </tr> <tr> <?php $query = $db->execute("select * from items where `player_id`=?", array($player->id)); while($item = $query->fetchrow()) { $query2 = $db->execute("select * from `blueprint_items` where `item_id`=?",array($item['item_id'])); $item2 = $query2->fetchrow(); echo "<td>"; echo "<a href='../item.php?id=".$item2['item_id']."'>".$item2['name']."</a><br>"; echo "<img src='" . $item2['img'] . "' width='100' height='100' style='border: 1px solid #cccccc'>"; } ?> </tr> </table> </div></div></div> but what i want is for when the code echos records, for it to echo it into a new row in my table above. im not really sure i can get this working.. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/ Share on other sites More sharing options...
aggrav8d Posted June 29, 2009 Share Posted June 29, 2009 I'm not sure what you mean when you say "what i want is for when the code echos records, for it to echo it into a new row in my table above." Can I make a suggestion? You might want to combine those queries with a LEFT JOIN to speed things up. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-865892 Share on other sites More sharing options...
seany123 Posted June 29, 2009 Author Share Posted June 29, 2009 whats a LEFT JOIN? sorry about my poor description about what im trying to do.. maybe the picture below will show you my problem... i only want 4 of the images showing per row. [attachment deleted by admin] Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-865901 Share on other sites More sharing options...
aggrav8d Posted June 29, 2009 Share Posted June 29, 2009 $query=$db->execute(" SELECT b.* FROM `items` i LEFT JOIN `blueprint_items` b ON (b.item_id=i.item_id) WHERE (player_id=?", array($player->id)); this way you get item_id, name, and img right away without having to do a whole bunch of extra queries. To limit your images to 4 per row you have a couple of options. You can use a counter in your loop and insert a <br> every 4th image. You can float left every image inside a div with a fixed width. There may be more options but I can't think of them right now. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-865919 Share on other sites More sharing options...
Psycho Posted June 29, 2009 Share Posted June 29, 2009 Hmmm, the database class youare using makes it difficult to really understand what you are doing - especially the fact that you are passing an array to the function. Are those values for Player ID and Item ID really arrays or is that just how the functions work? I am guessing they are NOT arrays and have modified the code accordingly. (I also assumed the second parameter is not required in $db->execute(). <div id="left_c"><div class="g_content"><h3> Your Points</h3><div class="g_text"> <table width="100%" align="center" cellspacing="10"> <?php $current_col = 1; $max_col = 4; $query = "SELECT * FROM items LEFT JOIN `blueprint_items` ON items.item_id = blueprint_items.item_id WHERE `player_id` = '{$player->id}'"; $result = $db->execute($query); while($record = $result->fetchrow()) { //Open new row if first column if($current_col==1) { echo "<tr>\n"; } //Display current record echo "<td>"; echo "<a href=\"../item.php?id={$result['item_id']}\">{$result['name']}</a><br>"; echo "<img src=\"{$result['img']}\" width=\"100\" height=\"100\" style=\"border: 1px solid #cccccc\">"; echo "</td>\n"; //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 1; } $current_col++; } //Close last row if needed if ($current_col!=1) { for(; $current_col<=$max_col; $current_col++) { echo "<td> </td>\n"; } } ?> </table> </div></div></div> Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-865962 Share on other sites More sharing options...
seany123 Posted June 30, 2009 Author Share Posted June 30, 2009 Hmmm, the database class youare using makes it difficult to really understand what you are doing - especially the fact that you are passing an array to the function. Are those values for Player ID and Item ID really arrays or is that just how the functions work? I am guessing they are NOT arrays and have modified the code accordingly. (I also assumed the second parameter is not required in $db->execute(). <div id="left_c"><div class="g_content"><h3> Your Points</h3><div class="g_text"> <table width="100%" align="center" cellspacing="10"> <?php $current_col = 1; $max_col = 4; $query = "SELECT * FROM items LEFT JOIN `blueprint_items` ON items.item_id = blueprint_items.item_id WHERE `player_id` = '{$player->id}'"; $result = $db->execute($query); while($record = $result->fetchrow()) { //Open new row if first column if($current_col==1) { echo "<tr>\n"; } //Display current record echo "<td>"; echo "<a href=\"../item.php?id={$result['item_id']}\">{$result['name']}</a><br>"; echo "<img src=\"{$result['img']}\" width=\"100\" height=\"100\" style=\"border: 1px solid #cccccc\">"; echo "</td>\n"; //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 1; } $current_col++; } //Close last row if needed if ($current_col!=1) { for(; $current_col<=$max_col; $current_col++) { echo "<td> </td>\n"; } } ?> </table> </div></div></div> using that it now echo's nothing. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-866446 Share on other sites More sharing options...
Psycho Posted June 30, 2009 Share Posted June 30, 2009 I give no guarantee that my code will work, especially since I am trying to write it against your database. I merely have provided the framework for a solution. I leave it to you to properly implement. Did you do ANY debugging AT ALL? (Plus I did state that I had to make some assumptions because of the class you are using). The first step would be to check the HTML created. If there is simply an opening and closing table tag, that would imply the query is not generating any results. If that's the case, then you should echo the query to the page to see that it is being created correctly and then to test it in the back end. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-866480 Share on other sites More sharing options...
seany123 Posted June 30, 2009 Author Share Posted June 30, 2009 are there no other ways of doing this? Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-866751 Share on other sites More sharing options...
seany123 Posted July 1, 2009 Author Share Posted July 1, 2009 i dont believe there is no known way of doing something like this using my class format and stuff. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867243 Share on other sites More sharing options...
MatthewJ Posted July 1, 2009 Share Posted July 1, 2009 I think he may have been implying more that you should not use a db class that you do not fully understand the workings of. People try and help, but when your stuff relies on classes and data they don't have access to, helping you troubleshoot is tough. Aside from that, aggrav8d and mjdamato gave you the answer. You just need to create a counter to use with the output loop... when it hits the max number of images per row, start a new one. Sounds pretty straight forward Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867252 Share on other sites More sharing options...
SaurabhAgarwal Posted July 1, 2009 Share Posted July 1, 2009 In your code move the <tr> and </tr> within the while loop. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867275 Share on other sites More sharing options...
seany123 Posted July 1, 2009 Author Share Posted July 1, 2009 In your code move the <tr> and </tr> within the while loop. doing that will mean that it shows 1 database record per line. i want it to show 4. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867277 Share on other sites More sharing options...
Psycho Posted July 1, 2009 Share Posted July 1, 2009 In your code move the <tr> and </tr> within the while loop. doing that will mean that it shows 1 database record per line. i want it to show 4. seany123, Did you even "read" the code provided above? As SaurabhAgarwal suggested it is the process that is important here. If you don't understand what the code is doing you shouldn't be using it. We tried to show a single query is more efficient for this purpose. I don't know anything about the database class you are using in order to properly implement that, but I have to believe it can work with a simple JOIN. But, you will have to figure that out yourself since you decided to use that class. I could have simply rewrote your "looping queries" code above, but that would only reenforce bad programming habits. Heck, if you were to try and understand the code provided you should be able to do that yourself. I did try and help you in my last post by asking you to check some things to see if we could narrow down the problem, but you failed to respond to any of those questions. I am more than happy to help, but for this problem to be solved will take participation on your part. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867295 Share on other sites More sharing options...
seany123 Posted July 1, 2009 Author Share Posted July 1, 2009 In your code move the <tr> and </tr> within the while loop. doing that will mean that it shows 1 database record per line. i want it to show 4. seany123, Did you even "read" the code provided above? As SaurabhAgarwal suggested it is the process that is important here. If you don't understand what the code is doing you shouldn't be using it. We tried to show a single query is more efficient for this purpose. I don't know anything about the database class you are using in order to properly implement that, but I have to believe it can work with a simple JOIN. But, you will have to figure that out yourself since you decided to use that class. I could have simply rewrote your "looping queries" code above, but that would only reenforce bad programming habits. Heck, if you were to try and understand the code provided you should be able to do that yourself. I did try and help you in my last post by asking you to check some things to see if we could narrow down the problem, but you failed to respond to any of those questions. I am more than happy to help, but for this problem to be solved will take participation on your part. after reading all the posts again i did look over the code you gave me again and decided that your solution is the only one available to me at the moment... so ive done exactly what you wrote except DIDNT use the JOIN query.. i instead just kept my queries and changed the values around.... anyway.... its basically done what i want except 1 little error, for some reason it started a new line and only showed 3 values instead of making it show 4.... im probably confusing you alot right now so ive taken a picture to show what i mean. [attachment deleted by admin] Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867400 Share on other sites More sharing options...
Psycho Posted July 1, 2009 Share Posted July 1, 2009 I see the problem. Within the small block that closes a row (i.e. </TR>) the code is changing the value of $current_col to 1, but then it is immediately increased by 1 after that block (2). Change this //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 1; } $current_col++; To this: //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 0; //<---Changed } $current_col++; The value will be set to 0, but then immediately increased to 1 (which is correct since the next item will be the first column. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-867418 Share on other sites More sharing options...
seany123 Posted July 3, 2009 Author Share Posted July 3, 2009 Yes that worked a treat thanks... just one more thing.. is there a way to work it so, if a query finds say $item['id'] more than once it will only echo the db details one time but echo something like the amount of records it found. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-868128 Share on other sites More sharing options...
seany123 Posted July 3, 2009 Author Share Posted July 3, 2009 does anyone know how to make the if statement check for multiple entries? Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-868467 Share on other sites More sharing options...
Psycho Posted July 3, 2009 Share Posted July 3, 2009 You can do that in PHP, but that would be stupid when you are using a database which does this naturally. You know it would have been helpful had you responded appropriately to my previous comment Are those values for Player ID and Item ID really arrays or is that just how the functions work? Since you did not provide the information up front I went the extra step to at least tell you what my assumptions were. But, then you failed to correct my false assumption. Had you done so we would have solved this earlier. Now that I know those values really are arrays, I'm pretty sure this will work to 1) use a single query and 2) add the ability to group the records. <div id="left_c"><div class="g_content"><h3> Your Points</h3><div class="g_text"> <table width="100%" align="center" cellspacing="10"> <?php $current_col = 1; $max_col = 4; $query = "SELECT b.item_id, b.name, b.img, COUNT(b.item_id) as item_count FROM items i LEFT JOIN `blueprint_items` b ON items.item_id = blueprint_items.item_id WHERE i.player_id IN ('" . implode("', '", array($player->id)) . "')"; $result = $db->execute($query); while($record = $result->fetchrow()) { //Open new row if first column if($current_col==1) { echo "<tr>\n"; } //Display current record echo "<td>"; echo "<a href=\"../item.php?id={$result['item_id']}\">{$result['name']} ({$result['item_count']})</a><br>"; echo "<img src=\"{$result['img']}\" width=\"100\" height=\"100\" style=\"border: 1px solid #cccccc\">"; echo "</td>\n"; //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 1; } $current_col++; } //Close last row if needed if ($current_col!=1) { for(; $current_col<=$max_col; $current_col++) { echo "<td> </td>\n"; } } ?> </table> </div></div></div> I give no guarantees this will work. but if it doesn't at least provide soe information of what didn't work right and do some simple debugging in order to help you further. For example, echo out the query so we can ensure it is being created properly Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-868498 Share on other sites More sharing options...
seany123 Posted July 3, 2009 Author Share Posted July 3, 2009 You can do that in PHP, but that would be stupid when you are using a database which does this naturally. You know it would have been helpful had you responded appropriately to my previous comment Are those values for Player ID and Item ID really arrays or is that just how the functions work? Since you did not provide the information up front I went the extra step to at least tell you what my assumptions were. But, then you failed to correct my false assumption. Had you done so we would have solved this earlier. Now that I know those values really are arrays, I'm pretty sure this will work to 1) use a single query and 2) add the ability to group the records. <div id="left_c"><div class="g_content"><h3> Your Points</h3><div class="g_text"> <table width="100%" align="center" cellspacing="10"> <?php $current_col = 1; $max_col = 4; $query = "SELECT b.item_id, b.name, b.img, COUNT(b.item_id) as item_count FROM items i LEFT JOIN `blueprint_items` b ON items.item_id = blueprint_items.item_id WHERE i.player_id IN ('" . implode("', '", array($player->id)) . "')"; $result = $db->execute($query); while($record = $result->fetchrow()) { //Open new row if first column if($current_col==1) { echo "<tr>\n"; } //Display current record echo "<td>"; echo "<a href=\"../item.php?id={$result['item_id']}\">{$result['name']} ({$result['item_count']})</a><br>"; echo "<img src=\"{$result['img']}\" width=\"100\" height=\"100\" style=\"border: 1px solid #cccccc\">"; echo "</td>\n"; //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 1; } $current_col++; } //Close last row if needed if ($current_col!=1) { for(; $current_col<=$max_col; $current_col++) { echo "<td> </td>\n"; } } ?> </table> </div></div></div> I give no guarantees this will work. but if it doesn't at least provide soe information of what didn't work right and do some simple debugging in order to help you further. For example, echo out the query so we can ensure it is being created properly to be honest, im just not that confident using that LEFT JOIN query thing.... ive never wrote queries in that way and i dont understand how they work. im sorry if i was being shit at explaining what i was doing... but i would like to compliment you for your persistence and general help. Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-868517 Share on other sites More sharing options...
Psycho Posted July 3, 2009 Share Posted July 3, 2009 If you are not using JOINS then you are not using your database to it's full potential. It's like buying a $3,000 gaming computer just to use the calculator! Take alook at this small tutorial on the subject. http://www.tizag.com/mysqlTutorial/mysqljoins.php Quote Link to comment https://forums.phpfreaks.com/topic/164148-solved-help-needed/#findComment-868537 Share on other sites More sharing options...
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