How: If file not found, assgin different file instead?

[ghurty]

I have the following code to pull up a "vendor" logo:

 

while($vendor = $GLOBALS['ISC_CLASS_DB']->Fetch($result)) {
		$GLOBALS['VendorId'] = $vendor['vendorid'];
		$GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";

 

Any suggestions how I can make it that if it does not find a file with that name, it will assign a different file to that variable instead?

 

 

Thanks

[abdfahim]

make use of the function file_exists

[ghurty]

Can you point me to a guide that explain the use of that in simple to understand ways?

 

Thanks

[abdfahim]

check the link

 

http://php.net/manual/en/function.file-exists.php

[ghurty]

So should this code work:

	while($vendor = $GLOBALS['ISC_CLASS_DB']->Fetch($result)) {
		$GLOBALS['VendorId'] = $vendor['vendorid'];
		$GLOBALS['VendorLogotemp'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";
		if(file_exists( $GLOBALS['VendorLogotemp'] )){
			$GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";
			} else {
				$GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/"."defaultlogo.png";
				}

 

 

Thanks

[abdfahim]

yup, though u r putting some extra line, u can do it like below

<?php
while($vendor = $GLOBALS['ISC_CLASS_DB']->Fetch($result)) {
      $GLOBALS['VendorId'] = $vendor['vendorid'];
      $GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";
      if(!file_exists( $GLOBALS['VendorLogo'] )){
            $GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/"."defaultlogo.png";
      }
}
?>

[ghurty]

I forgot about using "!".

 

Thanks a mil

[ghurty]

I tried

		$GLOBALS['VendorId'] = $vendor['vendorid'];
		$GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";
          if(!file_exists( $GLOBALS['VendorLogo'] )){
            $GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/"."defaultlogo.png";
      }

 

And no matter what, it goes to the defaultlogo. However if I comment out the whole  if !file_exists part, it displays the real logo. For some reason when checking, it considers the logos not found.

 

 

Thanks

[abdfahim]

see, you have to give absolute path (like "C:\apache\htdocs\logo\logo.jpg") or relative path (like "logo/logo.jpg" provided both your php file and the logo Folder resides on same folder) or use dot (../) to go up the directory.

[ghurty]

But what gets me confused is that how come when I just have:

	
$GLOBALS['VendorId'] = $vendor['vendorid'];
$GLOBALS['VendorLogo'] = GetConfig('ShopPath').'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png";

 

It does pull up and display the logo properly.

 

The php file and images are in two different directories.

[abdfahim]

I suggest,

1) print $GLOBALS['VendorLogo'] variable

2) then hardcode that thing to file_exists function and check whether file_exists working properly.

 

[ghurty]

Very interesting.

In order for the if filexists to work, I had to code in the exact path. the following example DID work. THank you for all the help.

 if(!file_exists( '/homepages/2/d3452/htdocs/test'.'/'.GetConfig('ImageDirectory').'/'."vendor_images/". $vendor['vendorid'] ."_logo.png")){