[SOLVED] Calendar Problem

twilitegxa · July 2, 2009

I can't figure out what I'm doing wrong in my code for this calendar. Upon running the script, I see the two pulldown menus for the month and year, and then I see the border for the table with the days of the week listed, but no values and above the table, three zeros are displayed for some reason. What is going on with my code? Here is the code for it:

<?php
define("ADAY", (60*60*24));
if (!checkdate($_POST[month], 1, $_POST[year]))
$nowArray = getdate();
$month = $nowArray['mon'];
$year = $nowArray['year'];
} else {
$month = $_POST[month];
$year = $_POST[year];
}
$start = mktime (12, 0, 0, $month, 1, $year);
$firstDayArray = getdate($start);
?>
<html>
<head>
<title><?php print "Calendar:
".$firstDayArray['month']." ".$firstDayArray['year'] ?></title>
</head>
<body>
<form method="post" action="<?php print "$_SERVER[php_SELF]"; ?>">
<select name="month">
<?php
$months = Array("January", "February", "March", "April", "May",
"June", "July", "August", "September", "October", "November", "December");

for ($x=1; $x <= count($months); $x++) {
print "\t<option value=\"$x\"";
print ($x == $month)?" SELECTED":"";
print ">".$month[$x-1]."\n";
}
?>
</select>
<select name="year">
<?php
for ($x=1980; $x<2010; $x++) {
print "\t<option";
print ($x == $year)?" SELECTED":"";
print ">$x\n";
}
?>
</select>
<input type="submit" value="Go!" />
</form>
<br />
<?php
$days = Array("Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday");

print "<TABLE BORDER="1" CELLPADDING="5">\n";
foreach ($days as $day) {
print "\t<td><b>$day</b></td>\n";
}
for ($count=0; $count < (6*7); $count++) {
$dayArray = getdate($start);
if (($count % 7) == 0) {
	if ($dayArray['mon'] != $month) {
		break;
	} else {
		print "</tr><tr>\n";
	}
}
if ($count < $firstDayArray['wday'] || $dayArray['mon'] != $month) {
	print "\t<td><br></td>\n";
} else {
	print "\t<td>".$dayArray['mday']."    </td>\n";
	$start += ADAY;
}
}
print "</tr></table>";
?>
</body>
</html>

RussellReal · July 2, 2009

add me : [email protected] I'll help for free.. Sorry for that unneeded extra info, I got reprimanded for 'advertising'.. the reason I want you to add me, is there is no demo of whats wrong, and its kinda hard to visualize this.. Anyway, add me or not its you call, however, maybe post some screenshots here

twilitegxa · July 5, 2009

Here is a screenshot of what the php outputs:

twilitegxa · July 5, 2009

I must have had some coding wrong, because I re-did my coding and now it is working. Here is the working code: :-)

<?php
define("ADAY", (60*60*24));
if (!checkdate($_POST['month'], 1, $_POST['year'])) {
$nowArray = getdate();
$month = $nowArray['mon'];
$year = $nowArray['year'];
} else {
$month = $_POST['month'];
$year = $_POST['year'];
}
$start = mktime (12, 0, 0, $month, 1, $year);
$firstDayArray = getdate($start);
?>
<html>
<head>
<title><?php print "Calendar:
".$firstDayArray['month']." ".$firstDayArray['year'] ?></title>
</head>
<body>
<form method="post" action="<?php print "$_SERVER[php_SELF]"; ?>">
<select name="month">
<?php
$months = Array("January", "February", "March", "April", "May",
"June", "July", "August", "September", "October", "November", "December");

for ($x=1; $x <= count($months); $x++) {
print "\t<option value=\"$x\"";
print ($x == $month)?" SELECTED":"";
print ">".$months[$x-1]."\n";
}
?>
</select>
<select name="year">
<?php
for ($x=1980; $x<2010; $x++) {
print "\t<option";
print ($x == $year)?" SELECTED":"";
print ">$x\n";
}
?>
</select>
<input type="submit" value="Go!" />
</form>
<br />
<?php
$days = Array("Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday");

print "<TABLE BORDER = 1 CELLPADDING=5>\n";
foreach ($days as $day) {
print "\t<td><b>$day</b></td>\n";
}
for ($count=0; $count < (6*7); $count++) {
$dayArray = getdate($start);
if (($count % 7) == 0) {
	if ($dayArray['mon'] != $month) {
		break;
	} else {
		print "</tr><tr>\n";
	}
}
if ($count < $firstDayArray['wday'] || $dayArray['mon'] != $month) {
	print "\t<td><br></td>\n";
} else {
	print "\t<td>".$dayArray['mday']."    </td>\n";
	$start += ADAY;
}
}
print "</tr></table>";
?>
</body>
</html>

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[SOLVED] Calendar Problem

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