[SOLVED] Rounding an Integer

[pacchiee]

Hello,

 

I want to round off an integer to end with 5 or 0 with PHP. For example:

 

21.4 should be rounded to 20

23.8 should be rounded to 25

26.4 should be rounded to 25

28.1 should be rounded to 30

 

and so on..

 

Please help. Thanks in Advance.

[nbarone]

<?php
function roundnum ($num, $nearest)
{
   $ret = 0;
   $mod = $num % $nearest;

   if ($mod >= 0)
     $ret = ( $mod > ( $nearest / 2)) ? $num + ( $nearest - $mod) : $num - $mod;
    else
     $ret = ( $mod > (-$nearest / 2)) ? $num - $mod : $num + ( -$nearest - $mod);
    return $ret;
}

echo roundnum (1234, 15);  // round to the nearest 15
echo roundnum (1234, 5); // round to the nearest 5
?>

 

http://www.markblah.com/2008/05/11/php-round-number-to-nearest-x/

[pacchiee]

Hello nbarone,

 

Thanks. That function rounds an integer to the nearest specified SINGLE number. But I want to round an integer to its nearest 5 or 10 BOTH.

[nbarone]

  Quote

Hello nbarone,

 

Thanks. That function rounds an integer to the nearest specified SINGLE number. But I want to round an integer to its nearest 5 or 10 BOTH.

 

Sorry, I guess I don't quite understand what you're trying to accomplish, this function rounds to the nearest 5.

[nbarone]

Maybe this is what you were looking for....it takes decimal into account...prolly not the most efficient way, but it works:

 

<?php
function roundnum ($num, $nearest)
{
   $ret = 0;
   $mod = $num % $nearest;

   if ($mod >= 0)
     $ret = ( $mod > ( $nearest / 2)) ? $num + ( $nearest - $mod) : $num - $mod;
    else
     $ret = ( $mod > (-$nearest / 2)) ? $num - $mod : $num + ( -$nearest - $mod);

 $dec_check = explode(".",$ret);
 if($dec_check[1]){
 	$tenth = $dec_check[1];
	if($tenth > 4){
		$ret = $ret+$nearest;
	}
}
    return floor($ret);
}

echo roundnum (17.5, 5); // = 20
echo roundnum (17.4, 5); // = 15
?>

[pacchiee]

Hello nbarone,

 

Thanks so much for you help. I got it working with the above function.

 

Cheers!