Confused with choice of 2 Arrays not working...

[fj1200]

Can anyone assist with this?    I need the code to select between 2 arrays and then display the results accordingly but it's not working...

 

	$arr_tower = "";

    if ($FOLDER == "101") $arr_tower = ('$kba');
if ($FOLDER == "201") $arr_tower = ('$kba');
if ($FOLDER == "301") $arr_tower = ('$uni');
if ($FOLDER == "401") $arr_tower = ('$uni');

echo 'FOLDER = '. $FOLDER . ' so Tower = '. $arr_tower;
echo ' --- foreach ('.$arr_tower.' as $key=>$tower)';

$kba = array(0=>"U1/2", 2=>"T2A", 3=>"U3", 4=>"U5/6", 5=>"T7");
$uni = array(0=>"T1", 1=>"T2", 2=>"T3", 3=>"T4", 4=>"T5", 5=>"T6", 6=>"T7", 7=>"T8", 8=>"T9", 9=>"T10"); 

echo "<table>";
foreach ($arr_tower as $key=>$tower)
{
$k = key($arr_tower); 
$val = $key + '15';
echo '<tr><td>'. $key .' => '. $tower. ' = '. $val .' --> '. $pbupdate[$val].'</td></tr>';
};
echo "</table>";

 

Got to be something simple.  If I just use one array and the array name rather than $arr_tower it works fine.  (btw - I'm adding 15 to $key because the db query result for this section starts at $pbupdate[15] and it works.)

 

This bit I added in as a test to see what exactly was being produced-

echo 'FOLDER = '. $FOLDER . ' so Tower = '. $arr_tower;
echo ' --- foreach ('.$arr_tower.' as $key=>$tower)';

- produces the correct string...

 

FOLDER = 401 so Tower = $uni --- foreach ($uni as $key=>$tower)

 

...however the web page shows this error:

 

"Warning: Invalid argument supplied for foreach() in C:\wamp\www\ProdBoard\pb_job_update.php on line 245"

 

...which is the actual foreach() line.    I've tried moving the arrays to the top of the section; to where they are now; all oevr the place...  is there something I'm missing here?

 

 

[ignace]

foreach ($arr_tower as $key=>$tower)

 

gives:

 

foreach ('$uni' as $key => $tower)

 

which gives you:

Warning: Invalid argument supplied for foreach() in C:\wamp\www\ProdBoard\pb_job_update.php on line 245

 

use the next technique instead (http://us3.php.net/manual/en/language.variables.variable.php):

if ($FOLDER == "101") $arr_name = 'kba';
if ($FOLDER == "201") $arr_name = 'kba';
if ($FOLDER == "301") $arr_name = 'uni';
if ($FOLDER == "401") $arr_name = 'uni';

$kba = array(0=>"U1/2", 2=>"T2A", 3=>"U3", 4=>"U5/6", 5=>"T7");
$uni = array(0=>"T1", 1=>"T2", 2=>"T3", 3=>"T4", 4=>"T5", 5=>"T6", 6=>"T7", 7=>"T8", 8=>"T9", 9=>"T10"); 

$arr_tower = ${$arr_name};
foreach ($arr_tower as $key => $tower) {
    ..

[sasa]

try

<?php
$arr_tower = "";
//$FOLDER=401;
    if ($FOLDER == "101") $arr_tower = ('kba');
if ($FOLDER == "201") $arr_tower = ('kba');
if ($FOLDER == "301") $arr_tower = ('uni');
if ($FOLDER == "401") $arr_tower = ('uni');

echo 'FOLDER = '. $FOLDER . ' so Tower = '. $arr_tower;
echo ' --- foreach ('.$arr_tower.' as $key=>$tower)';

$kba = array(0=>"U1/2", 2=>"T2A", 3=>"U3", 4=>"U5/6", 5=>"T7");
$uni = array(0=>"T1", 1=>"T2", 2=>"T3", 3=>"T4", 4=>"T5", 5=>"T6", 6=>"T7", 7=>"T8", 8=>"T9", 9=>"T10"); 

echo "<table>";
foreach ($$arr_tower as $key=>$tower)
{
$k = key($$arr_tower); 
$val = $key + '15';
echo '<tr><td>'. $key .' => '. $tower. ' = '. $val .' --> '. $pbupdate[$val].'</td></tr>';
};
echo "</table>";
?>

[fj1200]

Sasa's one worked - in a test output I got

 

FOLDER = 401 so Tower = uni --- foreach (uni as $key=>$tower)0 => T1 = 15 --> 0

1 => T2 = 16 --> 0

2 => T3 = 17 --> 0

3 => T4 = 18 --> 0

4 => T5 = 19 --> 0

5 => T6 = 20 --> 0

6 => T7 = 21 --> 0

7 => T8 = 22 --> 0

8 => T9 = 23 --> 0

9 => T10 = 24 --> 0

 

..and so I can do stuff with that.    Ignace - sorry - your one produced the same error, but they've both helped me a lot.  Never come across variable variables before - but then I'm no web programmer, just a sysadmin, but learning and using php to write tools for the job - and enjoying it (mostly).