[SOLVED] php links using $_GET

[pdpullmn612]

Hey guys,

 

I'm building a website and I have a question.

 

I want my URLs to be in a format like so:

 

http://mysite.com/resorts.php?resort=whatever

 

On resorts.php Im dynamically listing links for different pages.  What I want is that when a specific link is clicked, it displays the information of the selected link.  I have been able to do this with includes and what not.  There is only one problem.  When a link is clicked I need the list of links on the top of the page to disappear, so that only the information of the page requested is displayed.  I want it as if the link were clicked it basically looks like a whole new page, but maintains the URL format I specified above.  I think I have done it before, but I cannot think of where I found out how I did it.  Does this make sense?  Any help would be great.  Thanks in advanced.

 

Thanks,

 

Dave

[Box]

not really sure what your getting at.

 

you can use an if to check what the variable is and then display various pages:

 

ie:

if($_GET['resort']) {
echo ("The ".$_GET['resort']." is a nice place to go on holiday");
}
else if ($_GET['caravanpark']) {
echo ("Caravan parks are less fun, especially ".$_GET['caravanpark']);
}

[pdpullmn612]

I'm looking for something like this:

 

<?php

include("dbconnection.php");

$sql = "SELECT name, abbreviation FROM resorts ORDER BY name ASC;

$rs = mysql_query($sql) or die(mysql_error());

if(mysql_num_rows($rs)) {
     $output .= "<ul>";
     while ($row = mysql_fetch_array($rs, MYSQL_ASSOC)) {
          $output .= "<li><a href=resorts.php?state=$row[abbreviation]>$row[name]</a></li>";
     }
     $output .= "</ul>";
}

print $output;

$state = $_GET['state'];
if(isset($state)
{
    include($state . '.php'); //ex. This would display the contents of ct.php
}
else {
    include("index.php");
}

?>

 

What I want is the content from lets say ct.php to show up, but the links generated above it to go away so im only left with the content of ct.php.  I know I can use header("ct.php") to redirect the browser, but i want my links to be in the format like:

 

http://www.mysite.com/resorts.php?state=ct

 

instead of:

 

http://www.mysite.com/ct.php

 

hope that helps you guys better to help me.  Thanks in advanced for your help.

[Box]

<?php

include("dbconnection.php");

if (!$_GET['state'] {

$sql = "SELECT name, abbreviation FROM resorts ORDER BY name ASC;

$rs = mysql_query($sql) or die(mysql_error());

if(mysql_num_rows($rs)) {
     $output .= "<ul>";
     while ($row = mysql_fetch_array($rs, MYSQL_ASSOC)) {
          $output .= "<li><a href=resorts.php?state=$row[abbreviation]>$row[name]</a></li>";
     }
     $output .= "</ul>";
}

print $output;

}
else {

$state = $_GET['state'];
if(isset($state)
{
    include($state . '.php'); //ex. This would display the contents of ct.php
}
else {
    include("index.php");
}
}
?>

 

like that?

 

check to see if ?state was passed, if it was the don't show the list of links you have otherwise include the states page.

 

 

 

[HERATHEIM]

switch(true)
{
case($_GET['state']=='ct'):
{
  include("ct.php");
  break;
}
}

[pdpullmn612]

Thanks box you're the man.  Just what I was looking for.  I kinda feel stupid for not thinking about that sooner.  anyways, thanks a lot.