[SOLVED] if_int

[onthespot]

Any ideas why this doesnt work? Or could someone explain where I put this better?

 

$news=mysql_real_escape_string($_GET['news']);

if(!is_int($news)){

echo 'This piece of news does not exist. Back to <a href="news.php">News</a>';
exit();
}else{



}

 

This returns everything as not being an integer.

So even when the news=17, the message still displays.

Any ideas?

[PFMaBiSmAd]

is_int tests whether the type of a variable is integer. It does not test if the contents of a variable is an integer.

 

Use is_numeric or cast $news are as an integer.

[onthespot]

Works a treat, where would I ever use is_int then?

[PFMaBiSmAd]

If you wanted to test if the type of a variable is integer, i.e. not a string or not an array or not an object.

 

While it is true that a variable that is of type integer can only hold an integer, a variable that is a string can hold strings that have meaning when treated as an integer.

 

$_GET variables are by definition always strings and mysql_real_escape_string() only returns a sting (no matter what 'value' you give it), so $news in the posted code is a string that might or might not contain something that can be treated as an integer.