[SOLVED] data through pages

[contra10]

I'm trying to do this pagination script but everytime i click on "page 2" or "last" i get the same data in page one, basically nothing happens except for the url that changes

 

from something like this

http://localhost/outdoor/next/

to

http://localhost/outdoor/next/index.php?pagenum=2

<?php 
// Connects to your Database 
mysql_connect("localhost", "", "") or die(mysql_error()); 
mysql_select_db("deals") or die(mysql_error()); 

//This checks to see if there is a page number. If not, it will set it to page 1 
if (!(isset($pagenum))) 
{ 
$pagenum = 1; 
} 

//Here we count the number of results 
//Edit $data to be your query 
$querye = "SELECT * FROM `deal` WHERE `category` = 'Outdoor' and `time` = '704'";
$result = mysql_query($querye) or die(mysql_error());
$rows= mysql_num_rows($result);

//This is the number of results displayed per page 
$page_rows = 2; 
$es = ($rows/$page_rows);
//This tells us the page number of our last page 
$last = ceil($es);

//this makes sure the page number isn't below one, or more than our maximum pages 
if ($pagenum < 1) 
{ 
$pagenum = 1; 
} 
elseif ($pagenum > $last) 
{ 
$pagenum = $last; 
} 

//This sets the range to display in our query 
$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;
//This is your query again, the same one... the only difference is we add $max into it
$data_p = mysql_query("SELECT * FROM `deal` WHERE category = 'Outdoor' and time = '704' $max") or die(mysql_error()); 

//This is where you display your query results
while ($postede = mysql_fetch_assoc($data_p))
{
$title = "{$postede['title']}";
$imagename = "{$postede['imagename']}";
$time = "{$postede['time']}";
$titled = stripslashes($title);
$url = "{$postede['url']}";
$on= "on";
$off= "off";
echo "<tr>"; 
echo"<td width='10%' height='200'><a href='$url' target='_blank'><img src='http://localhost/includes/704/$imagename.jpg'></a></td>";
echo "</tr>"; 
echo "<tr><td></td></tr>";	
}
echo"<p>";

// This shows the user what page they are on, and the total number of pages
echo " --Page $pagenum of $last-- <p>";

// First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page.
if ($pagenum == 1) 
{
} 
else 
{
echo " <a href='{$_SERVER['PHP_SELF']}?p=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?p=$previous'>$Previous</a> ";
} 

//just a spacer
echo " ---- ";

//This does the same as above, only checking if we are on the last page, and then generating the Next and Last links
if ($pagenum == $last) 
{
} 
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?p=$next'>$next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?p=$last'>Last ->></a> ";
} 
?> 

[waynew]

Hi could you try

 

<?php 
// Connects to your Database 
mysql_connect("localhost", "", "") or die(mysql_error()); 
mysql_select_db("deals") or die(mysql_error()); 

$pagenum = 1;

//This checks to see if there is a page number. If not, it will set it to page 1 
if (!(isset($pagenum))) 
{ 
$pagenum = 1; 
} 

//Here we count the number of results 
//Edit $data to be your query 
$querye = "SELECT * FROM `deal` WHERE `category` = 'Outdoor' and `time` = '704'";
$result = mysql_query($querye) or die(mysql_error());
$rows= mysql_num_rows($result);

//This is the number of results displayed per page 
$page_rows = 2; 
$es = ($rows/$page_rows);
//This tells us the page number of our last page 
$last = ceil($es);

//this makes sure the page number isn't below one, or more than our maximum pages 
if ($pagenum < 1) 
{ 
$pagenum = 1; 
} 
elseif ($pagenum > $last) 
{ 
$pagenum = $last; 
} 

//This sets the range to display in our query 
$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;
//This is your query again, the same one... the only difference is we add $max into it
$data_p = mysql_query("SELECT * FROM `deal` WHERE category = 'Outdoor' and time = '704' $max") or die(mysql_error()); 

//This is where you display your query results
while ($postede = mysql_fetch_assoc($data_p))
{
   $title = "{$postede['title']}";
$imagename = "{$postede['imagename']}";
$time = "{$postede['time']}";
$titled = stripslashes($title);
$url = "{$postede['url']}";
$on= "on";
$off= "off";
   echo "<tr>"; 
echo"<td width='10%' height='200'><a href='$url' target='_blank'><img src='http://localhost/includes/704/$imagename.jpg'></a></td>";
   echo "</tr>"; 
   echo "<tr><td></td></tr>";   
}
echo"<p>";

// This shows the user what page they are on, and the total number of pages
echo " --Page $pagenum of $last-- <p>";

// First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page.
if ($pagenum == 1) 
{
} 
else 
{
echo " <a href='{$_SERVER['PHP_SELF']}?p=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?p=$previous'>$Previous</a> ";
} 

//just a spacer
echo " ---- ";

//This does the same as above, only checking if we are on the last page, and then generating the Next and Last links
if ($pagenum == $last) 
{
} 
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?p=$next'>$next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?p=$last'>Last ->></a> ";
} 
?>

[contra10]

i still have the same problem

[waynew]

Could you echo out $pagenum etc just before it goes to the select query?

[contra10]

This is what echoes out

$pagenum = 1

$last = 3

$es = 3

[contra10]

when i click pg 2. the results that are on the first page stays displayed