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Reaper0167

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echo '<a href="viewitem.php?sendto='.$row['id'].'"><img src="' . $row['thumb_1'] . '" border="0" alt=""></a>';

 

That is what I have on one of my pages on my site. Works great with the rest of the script.

I am trying to use that same line on another page on a different site, but it will not display the picture, just a little box with a red x.

any ideas? This is what I have so far, but the picture will not display( the line above works great for my first site. But I want to display the same stuff on a different site.

 

echo '<a href="http://www.originalsite.com/viewitem.php?sendto='.$row['id'].'"><img src="' . $row['thumb_1'] . '" border="0" alt=""></a>';

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Here is the full script that works great on the original site. But when I put the script on my other site, the picture will not display.

<?php
    include "connection2.php";
$sql = mysql_query("SELECT id, thumb_1, item_name, description, in_return, user_id FROM member_trades ORDER BY RAND() LIMIT 0, 6");
    echo "<table border='0' CELLPADDING=5 STYLE='font-size:16px'>";
    while ($row = mysql_fetch_array($sql))
    {
     echo "<tr><td align='center'>";
     echo '<a href="viewitem.php?sendto='.$row['id'].'"><img src="' . $row['thumb_1'] . '" border="0" alt=""></a>';
     echo "</td><td align='center'>";
     echo "".substr($row['item_name'],0,50),"";
     echo "</td><td align='center'>";
     echo substr($row['description'],0,50).'<a href="viewitem.php?sendto='.$row['id'].'" class="view_item"> ...more</a>';
     echo "</td><td align='center'>";
     echo substr($row['in_return'],0,50).'<a href="viewitem.php?sendto='.$row['id'].'" class="view_item"> ...</a>';
     echo "</td><td align='center'>";
     echo "</td></tr>";
     echo '<tr><td height="19" colspan="4">';
     echo '<hr width="550">';
     echo "</td></tr>";
    }
    echo "</table>";
    mysql_close();
?>

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