convert ereg to preg_match

[qualsiasi]

Hello, I tried to check preg_match syntax for be able to convert my pattern from ereg to preg_match function, but i have some problem understanding preg_match pattern building.

 

Can someone help me? The pattern i need to convert is this:

 

ereg("([0-9]{4}).([0-9]{1,2}).([0-9]{1,2})", $data[$nn], $regs)

 

its a simple date check loop, i would like to:

 

preg_match("...........................", $data[$nn], $regs)

 

Thanks in advance.

[aschk]

/facepalm

Did you even try?

 

<?php
preg_match("/([0-9]{4}).([0-9]{1,2}).([0-9]{1,2})/", $data[$nn], $regs)
?>

[rhodesa]

I think you are looking for:

preg_match('/([0-9]{4})\.([0-9]{1,2})\.([0-9]{1,2})/', $data[$nn], $matches);

but it can be shortened to:

preg_match('/(\d{4})\.(\d{1,2})\.(\d{1,2})/', $data[$nn], $matches);

[qualsiasi]

Thanks a lot rhodesa, solved.

 

@aschk: as far i had to edit a important script not wrote by me, that write sensible data on DB, where there is many of this call, i wonted to risk to do mistake by simple add basic slash, because after i saw some perl pattern example, i found it more complex and then i was not sure it was really right.