How to increment variable as the current year changes?

[mishasoni]

Hello to anyone out there -

 

PHP newbie here. I am trying to increment a number as the current year changes. For example, say in 2009 $age=20.  I want $age to automatically increase by 1 with each year...so, in 2010 $age = 21, for 2011 $age = 22, etc. 

 

This seems like it should be really simple, but I've come to an impasse on getting this to work. Could someone enlighten me as to the proper code to accomplish this?

 

Thanks in advance!!

[PFMaBiSmAd]

You should just store the date of birth and calculate the age whenever needed.

[bruce080]

I agree with the above post, but perhaps the following code might also help.

 

$year_diff = date("Y") - 1976;
echo $year_diff;   //will display 33

[bruce080]

Here is an entire birthday function if that is helpful also.

 

function birthday ($birthday)
{
list($year,$month,$day) = explode("-",$birthday);
$year_diff = date("Y") - $year;
$month_diff = date("m") - $month;
$day_diff = date("d") - $day;
if ($month_diff < 0) $year_diff--;
elseif (($month_diff==0) && ($day_diff < 0)) $year_diff--;
return $year_diff;
}

echo birthday("1980-07-02");

 

found at this link: http://snipplr.com/view/1357/calculate-age/

[mishasoni]

Great - thanks so much. 

 

One other related question: Is there a function for adding the "th", "rd", "nd", or "st" to a number?  Eg. 21st, 33rd, 42nd...etc.

[.josh]

see the thread you made about it.