heldenbrau Posted August 5, 2009 Share Posted August 5, 2009 I want to count the amount of rows in a database and display them, then increment the number and pass it to a filename. The filename needs to be called case1, case2, case3, case4, etc. depending on how many cases are already in the database. I have tried the following code but I keep getting Parse error: syntax error, unexpected T_VARIABLE $mysqli = new mysqli("localhost", "username", "pasword", "cases"); if ($mysqli === false) { die("ERROR: Could not connect to database. " . mysqli_connect_error()); } $sql = "SELECT COUNT(*) FROM 'cases'; if ($result = $mysqli->query($sql)) { $row = $result->fetch_assoc(); $add = $row; $add ++; echo "$add"; $newcase = "case"$add; }else{ die("ERROR: Could not execute query: $sql. " . $mysqli->error); } Quote Link to comment Share on other sites More sharing options...
alexdemers Posted August 5, 2009 Share Posted August 5, 2009 Well, you have a lot of errors in that script. First, it only get the rows 1 time since you don't have any sort of loops. Second, there's a parse error: "case"$add; which should be concatenated with a dot: "case".$add; Third, you try to select the table with its name surrounded in quotes. Remove the quotes after FROM. Here's a much better code. But, right now, every loops overwrites the variable $newcase which you should handle to your likings. <?php $mysqli = new mysqli("localhost", "username", "pasword", "cases"); if ($mysqli === false) { die("ERROR: Could not connect to database. " . mysqli_connect_error()); } $sql = "SELECT * FROM cases"; $count = 0; $result = $mysqli->query($sql); while ($row = mysqli_fetch_array($result)) { $count++; echo $count; $newcase = 'case'.$count; } // die("ERROR: Could not execute query: $sql. " . $mysqli->error); ?> Quote Link to comment Share on other sites More sharing options...
heldenbrau Posted August 5, 2009 Author Share Posted August 5, 2009 Thanks for typing that out. When I run it nothing happens, is that because there is no data in the database? The only data in the database is the columns waiting to be filled. Quote Link to comment Share on other sites More sharing options...
heldenbrau Posted August 5, 2009 Author Share Posted August 5, 2009 I changed the code to below, but the $count isn't incrementing, it just stays at 0 even when there is an entry in the database. <?php $mysqli = new mysqli("localhost", "username", "password", "cases"); if ($mysqli === false) { die("ERROR: Could not connect to database. " . mysqli_connect_error()); } $sql = "SELECT * FROM cases"; $count = 0; $result = $mysqli->query($sql); while ($row = mysqli_fetch_array($result)) { $count++; } if ($count==0){ $count++; } $newcase = 'case'.$count; echo $newcase; ?> Quote Link to comment Share on other sites More sharing options...
alexdemers Posted August 5, 2009 Share Posted August 5, 2009 Well, yes you need to have data in your table. Each row will increase the counter by 1. So if you have 100 records, $coutn will be = to 100 after the loop. Quote Link to comment Share on other sites More sharing options...
mikesta707 Posted August 5, 2009 Share Posted August 5, 2009 a much easier way to get the count of rows in your table is to use the mysqli_num_rows function this will get your count: $sql = "SELECT * FROM cases"; $result = $mysqli->query($sql); $count = mysqli_num_rows($result) EDIT: syntax error and also link to function: http://us2.php.net/manual/en/mysqli-result.num-rows.php Quote Link to comment Share on other sites More sharing options...
heldenbrau Posted August 5, 2009 Author Share Posted August 5, 2009 I added a record to the database, so $count should count that and = 1, it should then increment by 1 because of the $count++ so end up as 2 and print out case2. But it doesn't, it stays at 1. Quote Link to comment Share on other sites More sharing options...
mikesta707 Posted August 5, 2009 Share Posted August 5, 2009 well it doesn't get incremented because in your code if ($count==0){ $count++; } this never runs because count is not zero. if you want to always increment the count function, then remove the if statement and simply have $count++ Quote Link to comment Share on other sites More sharing options...
heldenbrau Posted August 5, 2009 Author Share Posted August 5, 2009 Using the num rows has sorted it out. Thanks. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.