if function

[desithugg]

umm i want to echo different images depending on if two rows are equal,lrger,smaller than each other
[code]
<?
$on = "4";
?>
<?php
$link = mysql_connect('localhost', $my_sql_password, $my_sql_username);
if (!$link) {
  die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db('tpf');
if (!$db_selected) {
  die('Could not select database: ' . mysql_error());
}
$query = "SELECT id FROM saad ORDER BY ID ASC";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
if ($on >= $row['id'])
{
$row['id'] = "<img src='/open.png'>";
}
if ($on < $row['id'])
{
$row['id'] = "<img src='/closed.png'>";
}
echo "(ID:". $row['id'] .")";
}
?>[/code]

the problem is it echos the same image weather the variable $on is bigger,equal to or smaller than the row $id

[desithugg]

nvm i got it