[SOLVED] is there a function to...

[The Little Guy]

is there a php funciton that will take something like this:

 

For command line:

/home/ryannaddy/phpsnips.com/images/s/image_name.jpg

 

and convert it to something that looks like this:

 

For Web:

/images/s/image_name.jpg

[jonsjava]

str_replace

<?php
$url = "home/ryannaddy/phpsnips.com/images/s/image_name.jpg";
str_replace("/home/rayannaddy/phpsnips.com","",$url);
?>

[The Little Guy]

no... I need to distribute the code, so that isn't going to work...

[jonsjava]

I was taking a guess. You were kinda vague.

 

Please explain further.  You mean take the working directory and remove everything up to the web directory?

[mikesta707]

you will probably want to look into some regex functions, like preg_replace. I'm not to good with regex (and there is another subforum dedicated to regex problems)

[kickstart]

Hi

 

If you want to find that section of the name then you will probably need to play around with various server variables:-

 

http://us3.php.net/manual/en/reserved.variables.server.php

 

All the best

 

Keith

[The Little Guy]

You mean take the working directory and remove everything up to the web directory?

 

yeah, I believe so...

 

I would like to do this:

 

$smalDir = $_SERVER['DOCUMENT_ROOT'].'/images/s/';
/*
~ 27 other lines of unrelated code
*/
foreach(glob($smalDir.'*') as $img){
     echo '<img src="'.someFunction($img).'" />';
}

[The Little Guy]

str_replace

<?php
$url = "home/ryannaddy/phpsnips.com/images/s/image_name.jpg";
str_replace("/home/rayannaddy/phpsnips.com","",$url);
?>

 

I used that, just changed it to:

 

str_replace($_SERVER['DOCUMENT_ROOT'], '',$img)